1. Given the following data, determine the orders with respect to the concentrations of substances A and B in the reaction [A] initial 0.10 M 0.20 M 0.30 M 0.20 M 0.10 M A + B [B]initial 0.10 M 0.10 M 0.10 M 0.20 M 0.20 M products Time for reaction 262 s 131 s 87 s 66 s 131 s
1. Given the following data, determine the orders with respect to the concentrations of substances A and B in the reaction [A] initial 0.10 M 0.20 M 0.30 M 0.20 M 0.10 M A + B [B]initial 0.10 M 0.10 M 0.10 M 0.20 M 0.20 M products Time for reaction 262 s 131 s 87 s 66 s 131 s
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What other two trials give me the same overall order of 2, using the same method as the one shown below..
![1. Given the following data, determine the orders with respect to the
concentrations of substances A and B in the reaction
A + B → products
[B] initial
[A] initial
0.10 M
0.20 M
0.30 M
0.20 M
0.10 M
0.10 M
0.10 M
0.10 M
0.20 M
0.20 M
Time for reaction
262 s
131 s
87 s
66 s
131 s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F08bb2a94-da17-43f2-90ab-4ad444df37b3%2Fc3825469-cf5b-49ef-a52a-85b64646e057%2Foimldsu_processed.png&w=3840&q=75)
Transcribed Image Text:1. Given the following data, determine the orders with respect to the
concentrations of substances A and B in the reaction
A + B → products
[B] initial
[A] initial
0.10 M
0.20 M
0.30 M
0.20 M
0.10 M
0.10 M
0.10 M
0.10 M
0.20 M
0.20 M
Time for reaction
262 s
131 s
87 s
66 s
131 s
![@262
131
B
2
0.5ª
=
262
131
=
K[0.10M] [0.101
K[0.20M] [TOM]"
ода
66.5
2
0.5a
So
262
131
0.8a
0.5=0.5
1 = a
=
=
= 0.5a
K[0.10Mja [ 0.10M]"
KL.10M] [ 0.20MJ
= 4
So
051
70.56
=
262
131
0.5 0.80
0.5
= b
0.5
Overall
= 4
= 0.5b
order=2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F08bb2a94-da17-43f2-90ab-4ad444df37b3%2Fc3825469-cf5b-49ef-a52a-85b64646e057%2F931vtrw_processed.png&w=3840&q=75)
Transcribed Image Text:@262
131
B
2
0.5ª
=
262
131
=
K[0.10M] [0.101
K[0.20M] [TOM]"
ода
66.5
2
0.5a
So
262
131
0.8a
0.5=0.5
1 = a
=
=
= 0.5a
K[0.10Mja [ 0.10M]"
KL.10M] [ 0.20MJ
= 4
So
051
70.56
=
262
131
0.5 0.80
0.5
= b
0.5
Overall
= 4
= 0.5b
order=2
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