1. Given the following data, determine the orders with respect to the concentrations of substances A and B in the reaction [A] initial 0.10 M 0.20 M 0.30 M 0.20 M 0.10 M A + B [B]initial 0.10 M 0.10 M 0.10 M 0.20 M 0.20 M products Time for reaction 262 s 131 s 87 s 66 s 131 s

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What other two trials give me the same overall order of 2, using the same method as the one shown below..

1. Given the following data, determine the orders with respect to the
concentrations of substances A and B in the reaction
A + B → products
[B] initial
[A] initial
0.10 M
0.20 M
0.30 M
0.20 M
0.10 M
0.10 M
0.10 M
0.10 M
0.20 M
0.20 M
Time for reaction
262 s
131 s
87 s
66 s
131 s
Transcribed Image Text:1. Given the following data, determine the orders with respect to the concentrations of substances A and B in the reaction A + B → products [B] initial [A] initial 0.10 M 0.20 M 0.30 M 0.20 M 0.10 M 0.10 M 0.10 M 0.10 M 0.20 M 0.20 M Time for reaction 262 s 131 s 87 s 66 s 131 s
@262
131
B
2
0.5ª
=
262
131
=
K[0.10M] [0.101
K[0.20M] [TOM]"
ода
66.5
2
0.5a
So
262
131
0.8a
0.5=0.5
1 = a
=
=
= 0.5a
K[0.10Mja [ 0.10M]"
KL.10M] [ 0.20MJ
= 4
So
051
70.56
=
262
131
0.5 0.80
0.5
= b
0.5
Overall
= 4
= 0.5b
order=2
Transcribed Image Text:@262 131 B 2 0.5ª = 262 131 = K[0.10M] [0.101 K[0.20M] [TOM]" ода 66.5 2 0.5a So 262 131 0.8a 0.5=0.5 1 = a = = = 0.5a K[0.10Mja [ 0.10M]" KL.10M] [ 0.20MJ = 4 So 051 70.56 = 262 131 0.5 0.80 0.5 = b 0.5 Overall = 4 = 0.5b order=2
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