How do I obtain the order (first order, second order, etc) of each trial.

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How do I obtain the order (first order, second order, etc) of each trial. 

TABLE 3: Calculations
Part 1
[H;O]i [KBrO3]i [HC]i
7.69 x10 M
7.69 x10 M
Trial
[Na2S2O3]i
[KI]i
Time
Rate
Temperature
1
1.12X10M 292 xt0
1.92x62M136 secs
|1.41x10-6
S.Sx10S
3.7x105
298.15 Kelvin
2
1.12x10.4
M 3.85 x10°m
1.92x6?M
70 secs
298,15 kelvin
1. 12x10.4
M |1. 12 X10M
1.15 x 10 M 1.92X6 M
52 secs
298,15 kelvin
4
1.12x 10.4
M |1. 12 x103,
7.(9 x10 M
3.85 x 102M
< "to *ר.S
34 secs
298,15 kelvin
1.12X10M1.62x10-4
1.15 x 10 M
3.85 x 102M
1.0x10*
38 secs
298.15 kelvin
Part II
[NazS2O3]i
[KI];
[H;O]i [KBrO3]i [HCI]i
Temperature
7.(9 x 103 M 1.12x6?m 295 secs 6Sx(0|273,15 Kelyin
10 secs 1-9x16 313,1S Kelvin
Trial
Time
Rate
1.12x10 M 292 x101
1.12x10*M 2.92 x10
1
1
7.(9 x103M
1.12X6?M
Transcribed Image Text:TABLE 3: Calculations Part 1 [H;O]i [KBrO3]i [HC]i 7.69 x10 M 7.69 x10 M Trial [Na2S2O3]i [KI]i Time Rate Temperature 1 1.12X10M 292 xt0 1.92x62M136 secs |1.41x10-6 S.Sx10S 3.7x105 298.15 Kelvin 2 1.12x10.4 M 3.85 x10°m 1.92x6?M 70 secs 298,15 kelvin 1. 12x10.4 M |1. 12 X10M 1.15 x 10 M 1.92X6 M 52 secs 298,15 kelvin 4 1.12x 10.4 M |1. 12 x103, 7.(9 x10 M 3.85 x 102M < "to *ר.S 34 secs 298,15 kelvin 1.12X10M1.62x10-4 1.15 x 10 M 3.85 x 102M 1.0x10* 38 secs 298.15 kelvin Part II [NazS2O3]i [KI]; [H;O]i [KBrO3]i [HCI]i Temperature 7.(9 x 103 M 1.12x6?m 295 secs 6Sx(0|273,15 Kelyin 10 secs 1-9x16 313,1S Kelvin Trial Time Rate 1.12x10 M 292 x101 1.12x10*M 2.92 x10 1 1 7.(9 x103M 1.12X6?M
Expert Solution
Step 1

Rate Law is given by,

Rate=k[Na2S2O3]a[KI]b[KBrO3]c[HCl]d

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