The experimental data for the reaction below is given: HBRO3 + 5HB 3B12 + 3 H2O [HBRO3] [HBr] Initial Trial (M) (M) Rate (MIs) 1 0.10 0.10 8.0 x 104 0.20 0.10 1.6 x 10-3 0.20 0.20 3.2 x 10-3 0.10 0.10 3.2 x 10-3 2. 3. 4.
The experimental data for the reaction below is given: HBRO3 + 5HB 3B12 + 3 H2O [HBRO3] [HBr] Initial Trial (M) (M) Rate (MIs) 1 0.10 0.10 8.0 x 104 0.20 0.10 1.6 x 10-3 0.20 0.20 3.2 x 10-3 0.10 0.10 3.2 x 10-3 2. 3. 4.
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.58PAE
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![The experimental data for the reaction below is given:
HBRO3 + 5HBR
3Br2 + 3 H2O
[HBRO3] [HBr]
(M)
Initial
Rate
Trial
(M/s)
0.10
0.10
8.0 x 104
0.20
0.10
1.6 x 10-3
3
0.20
0.20
3.2 x 10-3
0.10
0.10
3.2x10-3
2.
4.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5d51f552-c96d-4ab0-bc52-d4683176ed37%2F8d0068a7-0912-48da-b564-910a0aa3db07%2Fx5bkbg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The experimental data for the reaction below is given:
HBRO3 + 5HBR
3Br2 + 3 H2O
[HBRO3] [HBr]
(M)
Initial
Rate
Trial
(M/s)
0.10
0.10
8.0 x 104
0.20
0.10
1.6 x 10-3
3
0.20
0.20
3.2 x 10-3
0.10
0.10
3.2x10-3
2.
4.
Transcribed Image Text:Use the data to calculate the specific rate constant K and overall order of the reaction.
O K= 0.080 M-1s-1, overall order = 2nd
O K= 0.77 M-1s-1, overall order = 2nd
O K= 0.080 M-1s1, overall order = 1St
OK= 0.77 M-1s-1, overall order = 3rd
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