Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 8: Deriving the Integrated Rate Law for a Zero-Order Reaction**
*(Hint: Show your work.)*
In this problem, students are tasked with deriving the integrated rate law for a chemical reaction that follows zero-order kinetics. Zero-order reactions have a rate that is independent of the concentration of the reactant. The solution involves mathematical steps demonstrating how the reaction rate is expressed in terms of the change in concentration over time.
---
**Detailed Explanation:**
For a zero-order reaction, the rate of reaction is constant and can be represented as:
\[ \text{Rate} = k \]
Where:
- \( k \) is the zero-order rate constant.
The rate of change of concentration with time for a zero-order reaction is given by the differential rate equation:
\[ \frac{d[A]}{dt} = -k \]
Integrating this equation with respect to time \( t \) gives the integrated rate law:
\[ [A] = [A_0] - kt \]
Where:
- \([A]\) is the concentration of the reactant at time \( t \).
- \([A_0]\) is the initial concentration of the reactant.
- \( t \) is the time.
This equation shows how the concentration of the reactant decreases linearly over time, indicating a constant reaction rate characteristic of zero-order kinetics.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fde0d8321-fd20-4016-824d-bef6e7bc20e4%2Fad93d738-961d-453a-944b-4c8a1b3bc0c2%2Fodglols_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 8: Deriving the Integrated Rate Law for a Zero-Order Reaction**
*(Hint: Show your work.)*
In this problem, students are tasked with deriving the integrated rate law for a chemical reaction that follows zero-order kinetics. Zero-order reactions have a rate that is independent of the concentration of the reactant. The solution involves mathematical steps demonstrating how the reaction rate is expressed in terms of the change in concentration over time.
---
**Detailed Explanation:**
For a zero-order reaction, the rate of reaction is constant and can be represented as:
\[ \text{Rate} = k \]
Where:
- \( k \) is the zero-order rate constant.
The rate of change of concentration with time for a zero-order reaction is given by the differential rate equation:
\[ \frac{d[A]}{dt} = -k \]
Integrating this equation with respect to time \( t \) gives the integrated rate law:
\[ [A] = [A_0] - kt \]
Where:
- \([A]\) is the concentration of the reactant at time \( t \).
- \([A_0]\) is the initial concentration of the reactant.
- \( t \) is the time.
This equation shows how the concentration of the reactant decreases linearly over time, indicating a constant reaction rate characteristic of zero-order kinetics.
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