6. Consider the following reaction(Criegee Ozonolysis) k 302 203 (Fast) C„H4 + O3 k2 C2H,O3 (Slow) Using the steady-state approximation and pre-equilibrium approximation, calculate the reaction speed of both reactions. Also, find the condition that those two approximations become equivalent.
6. Consider the following reaction(Criegee Ozonolysis) k 302 203 (Fast) C„H4 + O3 k2 C2H,O3 (Slow) Using the steady-state approximation and pre-equilibrium approximation, calculate the reaction speed of both reactions. Also, find the condition that those two approximations become equivalent.
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In this question, using the steady-state approximation assuming that [O3] is steady throughout, should I consider three reaction speeds (k1, k-1, k2) equivalent, or should I double the reaction speed of ozone production (3O2 → 2O3)?
In other words, is -d[O3]/dt = k1[O2]3 - k-1[O3]2 - k2[O3] = 0, true or false?
![6. Consider the following reaction(Criegee Ozonolysis)
k
302
203 (Fast)
C„H4 + O3
k2
C2H,O3 (Slow)
Using the steady-state approximation and pre-equilibrium approximation, calculate the
reaction speed of both reactions. Also, find the condition that those two approximations
become equivalent.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7472228e-7672-4a88-b82a-3b059e9cf3aa%2F436e4101-571b-44cf-84ff-fac068bde926%2Fxy2o1e_processed.png&w=3840&q=75)
Transcribed Image Text:6. Consider the following reaction(Criegee Ozonolysis)
k
302
203 (Fast)
C„H4 + O3
k2
C2H,O3 (Slow)
Using the steady-state approximation and pre-equilibrium approximation, calculate the
reaction speed of both reactions. Also, find the condition that those two approximations
become equivalent.
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