In the hydrogenation of ethylene using a nickel catalyst, the initial concentration of ethylene is 1.50 mol-L. and its rate constant (k) is 0.0012 mol-L-Determine the rate of reaction if it follows a zero- order reaction mechanism.

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### Zero-Order Reactions

**Learning Goal:**  
To understand zero-order reactions.

Chemical kinetics studies the speed of chemical reactions and their influencing factors. The speed of a reaction is the rate of change in concentrations of reactants and products, expressed through rate laws.

For a general reaction:
\[ aA + bB \rightarrow gG + hH \]

The rate law is:
\[ \text{rate of reaction} = k[A]^m[B]^n \]

where the coefficients \(m\) and \(n\) are experimentally determined, while \(a, b, g, h\) are stoichiometric coefficients unrelated to \(m\) and \(n\).

A zero-order reaction has a rate law where the sum \(m + n + \ldots = 0\). Thus, if there's one reactant, the rate is independent of its concentration.

In zero-order reactions, the concentration versus time graph is a straight line. The rate-law equation is analogous to a straight line equation \(y = mx + b\).

**Exercise:**

- **Multiple Choice:**
  - The units for the rate constant and reaction rate are the same
  - Zero-order reactions slow down as they proceed
  - Reactant concentration changes nonlinearly
  - Reaction rate does not equal the rate constant
  - Higher reactant concentration does not increase rate

**Correct Answer:**
- A zero-order reaction is independent of reactant concentration. Features include:
  1. Concentration vs. time graph is a straight line with a negative slope equal to the rate constant.
  2. The rate of reaction equals the rate constant.
  3. Units: \([L \cdot mol^{-1} \cdot s^{-1}]\).

**Examples:** Photochemical and surface reactions.

**Part B:**

In the hydrogenation of ethylene using a nickel catalyst, initial ethylene concentration is \(1.50 \, \text{mol} \cdot \text{L}^{-1}\), and \(k = 0.0012 \, \text{mol} \cdot \text{L}^{-1} \cdot \text{s}^{-1}\). Calculate the reaction rate assuming a zero-order mechanism, expressed to two significant figures with appropriate units.

- **Incorrect Attempt:**
  - Rate = 541.6 \(\text{mol/L}\) (Try again
Transcribed Image Text:### Zero-Order Reactions **Learning Goal:** To understand zero-order reactions. Chemical kinetics studies the speed of chemical reactions and their influencing factors. The speed of a reaction is the rate of change in concentrations of reactants and products, expressed through rate laws. For a general reaction: \[ aA + bB \rightarrow gG + hH \] The rate law is: \[ \text{rate of reaction} = k[A]^m[B]^n \] where the coefficients \(m\) and \(n\) are experimentally determined, while \(a, b, g, h\) are stoichiometric coefficients unrelated to \(m\) and \(n\). A zero-order reaction has a rate law where the sum \(m + n + \ldots = 0\). Thus, if there's one reactant, the rate is independent of its concentration. In zero-order reactions, the concentration versus time graph is a straight line. The rate-law equation is analogous to a straight line equation \(y = mx + b\). **Exercise:** - **Multiple Choice:** - The units for the rate constant and reaction rate are the same - Zero-order reactions slow down as they proceed - Reactant concentration changes nonlinearly - Reaction rate does not equal the rate constant - Higher reactant concentration does not increase rate **Correct Answer:** - A zero-order reaction is independent of reactant concentration. Features include: 1. Concentration vs. time graph is a straight line with a negative slope equal to the rate constant. 2. The rate of reaction equals the rate constant. 3. Units: \([L \cdot mol^{-1} \cdot s^{-1}]\). **Examples:** Photochemical and surface reactions. **Part B:** In the hydrogenation of ethylene using a nickel catalyst, initial ethylene concentration is \(1.50 \, \text{mol} \cdot \text{L}^{-1}\), and \(k = 0.0012 \, \text{mol} \cdot \text{L}^{-1} \cdot \text{s}^{-1}\). Calculate the reaction rate assuming a zero-order mechanism, expressed to two significant figures with appropriate units. - **Incorrect Attempt:** - Rate = 541.6 \(\text{mol/L}\) (Try again
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