The reaction described by the equation 03(g)+NO(g)-02(g)+NO2(g)O3(g)+NO(g)-02(g)+NO2(g) has, at 310 K, the rate law rate of reaction=k[O3][NO]k=3.0×106 M-1-s-1rate of reaction=k[O3][NÓ]k=3.0×106 M-1's-1 Given that [03]=4.0x10-4 M[03]=4.0x10-4 M and [NO]=8.0x10-5 M[NO]=8.0x10-5 M at t=0,t=0, calculate the rate of the reaction at /=0. rate: What is the overall order of this reaction?

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The reaction described by the equation
03(g)+NO(g)-02(g)+NO2(g)03(g)+NO(g)-02(g)+NO2(g)
has, at 310 K, the rate law
rate of reaction=k[O3][NO]k=3.0×106 M-1's-1rate of
reaction=k[03][NÕ]k=3.0×106 M-1's-1
Given that [03]=4.0x10-4 M[O3]=4.0x10-4 M and [NO]=8.0x10-5
M[NO]=8.0x10-5 M at t=0,t=0, calculate the rate of the reaction at t=0.
rate:
What is the overall order of this reaction?
Transcribed Image Text:The reaction described by the equation 03(g)+NO(g)-02(g)+NO2(g)03(g)+NO(g)-02(g)+NO2(g) has, at 310 K, the rate law rate of reaction=k[O3][NO]k=3.0×106 M-1's-1rate of reaction=k[03][NÕ]k=3.0×106 M-1's-1 Given that [03]=4.0x10-4 M[O3]=4.0x10-4 M and [NO]=8.0x10-5 M[NO]=8.0x10-5 M at t=0,t=0, calculate the rate of the reaction at t=0. rate: What is the overall order of this reaction?
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