Trial 1 2 3 4 time (s) 250 135 60 120 Rate 0.00317 0.0059 0.013 0.00608 [BrO3-] (M) [H+] (M) 0.020 0.0012 0.0024 0.0012 0.0012 0.020 0.040 0.020 [1-] (M) 0.0060 0.0060 0.0060 0.012

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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how do you calculate the rate constant, k, by using the orders, a, b, and c, that you calculated above, the rate
and concentration data from Trial 1. Remember that a rate constant must have units. Write the full rate law for the reaction below including all the numbers you just calculated. 

Trial
1
12
13
14
time (s)
250
135
60
120
Rate
0.00317
0.0059
0.013
0.00608
[BrO3-] (M) [H+] (M)
0.0012
0.020
0.0024
0.0012
0.0012
0.020
0.040
0.020
[1-] (M)
0.0060
0.0060
0.0060
0.012
Transcribed Image Text:Trial 1 12 13 14 time (s) 250 135 60 120 Rate 0.00317 0.0059 0.013 0.00608 [BrO3-] (M) [H+] (M) 0.0012 0.020 0.0024 0.0012 0.0012 0.020 0.040 0.020 [1-] (M) 0.0060 0.0060 0.0060 0.012
Trail 1
=
b = 2
C = 1
b
0.00317 = K[0.0012] a [0.0201 [0.0000]°
Transcribed Image Text:Trail 1 = b = 2 C = 1 b 0.00317 = K[0.0012] a [0.0201 [0.0000]°
Expert Solution
Step 1

Let the rate law :

 r= K [BrO3-]a[H+]b[I-]         (I)

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