16 **Drug Elimination Kinetics Educational Exercise**Title: First-Order Kinetics in Drug Elimination---**Topic:** Understanding First-Order Kinetics in Drug Elimination from the Body**Objective:** Learn how to calculate the concentration of a drug in the bloodstream over time using first-order kinetics and the concept of half-life.### Problem Statement:The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half-life of 33 minutes.**Scenario:**Suppose in a particular patient the concentration of this drug in the bloodstream immediately after injection is 0.98 μg/mL. What will the concentration be 165 minutes later?**Instructions:**- Round your answer to 2 significant digits.**Data Given:**- Initial concentration (C₀): 0.98 μg/mL- Half-life (t₁/₂): 33 minutes- Time elapsed (t): 165 minutes**Objective:**Calculate the concentration (C) of the drug in the bloodstream after 165 minutes.### Solution Steps:**Using the first-order kinetics formula:**\[ C = C₀ \times \left( \frac{1}{2} \right)^{\frac{t}{t₁/₂}} \]Where:- \( C \) is the concentration after time \( t \).- \( C₀ \) is the initial concentration.- \( t \) is the time elapsed.- \( t₁/₂ \) is the half-life.Plug in the values:\[ C = 0.98 \, \text{μg/mL} \times \left( \frac{1}{2} \right)^{\frac{165}{33}} \]\[ \frac{165}{33} = 5 \]\[ C = 0.98 \, \text{μg/mL} \times \left( \frac{1}{2} \right)^5 \]\[ \left( \frac{1}{2} \right)^5 = \frac{1}{32} \]\[ C = 0.98 \, \text{μg/mL} \times \frac{1}{32} \]\[ C = 0.030625 \, \text{μg/mL} \]**Rounded to 2 significant digits:**\[

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The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half life of 33 minutes. Suppose in a particular patient the concentration of this drug in the bloodstream immediately after injection is 0.98 µg/mL. What will the concentration be 165 minutes later? Round your answer to 2 significant digits. mL 3 ? x10 X