Abs vs Time Trial 1 Ln(Abs) vs Time Trial 1 1/Abs vs Time Trial 1 0.35 0.00 9.00 20 40 60 80 100 120 140 160 180 8.00 y= 0.0297x + 2.4624 R=0.989 0.3 y=-0.0012x + 0.3231 -a.s0 7.00 R= 0.9771 0.25 y=0.0059x - 1.0624 6.00 0.2 -1.00 R0.9993 5.00 0.15 4.00 . .. -1.50 3.00 0.1 2.00 0.05 -2.00 1.00 0.00 20 40 60 80 100 120 140 160 180 -2.50 20 40 60 80 100 120 140 160 180

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need help finding the rate law for each graph. The first graph is in order zero, the middle is in order first and the last is in order second. 

Abs vs Time Trial 1
Ln(Abs) vs Time Trial 1
1/Abs vs Time Trial 1
0.35
0.00
9.00
20
40
60
80
100
120
140
160
180
8.00
y = 0.0297x + 2.4624
R2 = 0.989
0.3
y = -0.0012x + 0.3231
R2 = 0.9771
-0.50
7.00
0.25
y = -0.0059x - 1.0624
R2 = 0.9993
6.00
0.2
-1.00
5.00
...
4.00
0.15
-1.50
3.00
....
0.1
2.00
0.05
-2.00
1.00
0.00
40
60
80
100
120
140
160
180
-2.50
20
40
60
80
100
120
140
160
180
20
Transcribed Image Text:Abs vs Time Trial 1 Ln(Abs) vs Time Trial 1 1/Abs vs Time Trial 1 0.35 0.00 9.00 20 40 60 80 100 120 140 160 180 8.00 y = 0.0297x + 2.4624 R2 = 0.989 0.3 y = -0.0012x + 0.3231 R2 = 0.9771 -0.50 7.00 0.25 y = -0.0059x - 1.0624 R2 = 0.9993 6.00 0.2 -1.00 5.00 ... 4.00 0.15 -1.50 3.00 .... 0.1 2.00 0.05 -2.00 1.00 0.00 40 60 80 100 120 140 160 180 -2.50 20 40 60 80 100 120 140 160 180 20
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