I need help finding the rate law for each graph. The first graph is in order zero, the middle is in order first and the last is in order second. ### Analysis of Absorbance vs Time in a Chemical ReactionThis image showcases three different graphical analyses of absorbance (Abs) against time, as part of a kinetic study in a chemical reaction. Each graph provides insights into the reaction order and helps to understand the relationship between absorbance and time.#### Graph 1: Abs vs Time Trial 1- **Description**: This graph plots direct absorbance against time.- **Equation**: The line of best fit is provided by the equation \( y = -0.0012x + 0.3231 \).- **R-squared Value**: \( R^2 = 0.9771 \), indicating a strong linear correlation.- **Interpretation**: The negative slope suggests a decrease in absorbance over time.#### Graph 2: Ln(Abs) vs Time Trial 1- **Description**: This plot presents the natural logarithm of absorbance against time.- **Equation**: The linear relationship is described by \( y = -0.0095x - 1.0624 \).- **R-squared Value**: \( R^2 = 0.9993 \), showing an excellent fit.- **Interpretation**: The ln(absorbance) plot suggests a first-order reaction, given the strong linearity and the high R-squared value.#### Graph 3: 1/Abs vs Time Trial 1- **Description**: Here, the inverse of absorbance is plotted against time.- **Equation**: The best fit line is represented by \( y = 0.0297x + 2.4262 \).- **R-squared Value**: \( R^2 = 0.989 \), also indicating a strong linear fit.- **Interpretation**: This graph suggests a second-order reaction based on the linearity observed when plotting 1/absorbance.### ConclusionThe analysis of these graphs supports kinetic modeling of the reaction. The Ln(Abs) vs Time graph, with its highly linear fit, suggests a first-order reaction. This detailed graphical analysis aids in understanding underlying reaction dynamics and is essential for predicting reaction behavior over time.

A question based on chemical kinetics, which is to be accomplished.

Abs vs Time Trial 1 Ln(Abs) vs Time Trial 1 1/Abs vs Time Trial 1 0.35 0.00 9.00 20 40 60 80 100 120 140 160 180 8.00 y= 0.0297x + 2.4624 R=0.989 0.3 y=-0.0012x + 0.3231 -a.s0 7.00 R= 0.9771 0.25 y=0.0059x - 1.0624 6.00 0.2 -1.00 R0.9993 5.00 0.15 4.00 . .. -1.50 3.00 0.1 2.00 0.05 -2.00 1.00 0.00 20 40 60 80 100 120 140 160 180 -2.50 20 40 60 80 100 120 140 160 180

Abs vs Time Trial 1 Ln(Abs) vs Time Trial 1 1/Abs vs Time Trial 1 0.35 0.00 9.00 20 40 60 80 100 120 140 160 180 8.00 y= 0.0297x + 2.4624 R=0.989 0.3 y=-0.0012x + 0.3231 -a.s0 7.00 R= 0.9771 0.25 y=0.0059x - 1.0624 6.00 0.2 -1.00 R0.9993 5.00 0.15 4.00 . .. -1.50 3.00 0.1 2.00 0.05 -2.00 1.00 0.00 20 40 60 80 100 120 140 160 180 -2.50 20 40 60 80 100 120 140 160 180

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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