Given, f=84 Hz .: W=2πf =2πT x 84 = 527.7876 for Capacitor (xc) = 1 1 jwc j527.7876 x 2×15-6 =-3947.35082 for Inductor (x) = jwL = j527.7876 x 50 x×10 Now Redraw the circuit in =j26-38942 given frequency 3640 -1947.35082 th V + {2k-2 √x3j26.3894 + 44233 Vo 1VX Apply Nodal √x -36400+ Vx Vx Vx-Vo + + 2000 j26.3894 j947.3508 360° = x[ Vx [2000 4 + j26.3894 + 0947.3505 0947.3500 == Apply Nodal on Vo, 3610° = 10.036842 L-89.2224) Vx+ Vo 0947-3508 V₂ Vo-Vx + 0.1Vx+ 4000 947.3508 4000 j947. -]+ Vx [0.1+ 1947. 308 13508 / +1 (0.001085 £76.6757) №6 + ·(0. from quation ①and ② 1947.3508 =O • 100006 L_0.605°) Vx=0 =O Vx=372.4317 L9.174567° Volts 16=34334.5034 2111.894° VOHS LTspice XVII - [Draft2] File Edit Hierarchy View Simulate Tools Window Help Aa .op I1 AC 36 ← SINE(0 36 84 0.0119) .ac lin 1 383,2743 383,2743 This is ground. ○ Ara C1 2μ 0.1 Vx R1 Vx 2k 50m G1 + > 0 0 Vo 4k х 5 14:38 9.11.2024

Given, f=84 Hz .: W=2πf =2πT x 84 = 527.7876 for Capacitor (xc) = 1 1 jwc j527.7876 x 2×15-6 =-3947.35082 for Inductor (x) = jwL = j527.7876 x 50 x×10 Now Redraw the circuit in =j26-38942 given frequency 3640 -1947.35082 th V + {2k-2 √x3j26.3894 + 44233 Vo 1VX Apply Nodal √x -36400+ Vx Vx Vx-Vo + + 2000 j26.3894 j947.3508 360° = x[ Vx [2000 4 + j26.3894 + 0947.3505 0947.3500 == Apply Nodal on Vo, 3610° = 10.036842 L-89.2224) Vx+ Vo 0947-3508 V₂ Vo-Vx + 0.1Vx+ 4000 947.3508 4000 j947. -]+ Vx [0.1+ 1947. 308 13508 / +1 (0.001085 £76.6757) №6 + ·(0. from quation ①and ② 1947.3508 =O • 100006 L_0.605°) Vx=0 =O Vx=372.4317 L9.174567° Volts 16=34334.5034 2111.894° VOHS LTspice XVII - [Draft2] File Edit Hierarchy View Simulate Tools Window Help Aa .op I1 AC 36 ← SINE(0 36 84 0.0119) .ac lin 1 383,2743 383,2743 This is ground. ○ Ara C1 2μ 0.1 Vx R1 Vx 2k 50m G1 + > 0 0 Vo 4k х 5 14:38 9.11.2024

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

3. Find Idc, Vdc and the capacitance that will force the Vr(pp) to 3mV. Draw the output waveform across the capacitor. Fin=60HZ. DC output I DC without AC input DC with сарacitor сарacitor D Si RL 800 ohms 220Vrms a = 15:2 ww 00000
Show the capacitors, whether it is effective at low or high frequencsies Draw low frequency small-signal-equivalent circuit. AND LOWER corner is 82Hz frequency. Design the circuit. Draw the high frequency small-signal-equivalent circuit. AND UP-CORNER İS 172Hz frequency. DESİGN THE CIRCUIT.
Measure the phase shift.( Need only handwritten solution please otherwise downvote)
O c.2 VA Q= 2000 VAR, pf = 0.9 (leading). The power in complex form is: %3D Select one: O a. 2000+ j41.29.8 VA O b.4129.8- j2000 VA Oc. 2000- j4129.8 VA O d. 4129.8+ j2000 VA
IN A SERIES RLC CIRCUIT DRIVEN BY SINUSOIDAL INPUT SIGNAL, THE PHASE BETWEEN THE CURRENT AND THE INPUT VOLTAGE IS PLOTTED IN THE NEXT GRAPH. When the frequency f = 60 kHz the phase (in radians) between the voltage on the capacitor and the voltage on the inductor is about: 1.6 1.2 0.8 0.4 -0.4 -0.8 -1.2 -1.6 1 10 100 1000 Frequency (f), kHz O a. zero O b. -1.57 O c. 0.003 O d. 1.57 O e. 3.14 Phase (0 ), rad
3- Analyze the system shown below to find the output waveform, Vout, assume the capacitor voltage value is -1.0 V at t-0 and RC-1 msec. -0.5 -1.0 V(1), V 1.0 0.5 R $ AAA f, msec
Design a sequential circuit that has one input (x) and one output (z) to detect z=1) the input pattern (10001) or (000) with overlapping present by using More model and JK-F/Fs. Draw the output on the oscilloscope for the input pattern
I need the answer as soon as possible
Find transfer function Eo(s)/Ei(s) Do it my complex impediance method and show diagram Provide right and complete answer do each steps with loops
A 100 Hz sinusoid is sampled at thrice the nyquist rate. Then how many samples are obtained in 2sec.
i need the answer quickly
solve this please