The goal of this problem is to show how the conjugate symmetry relation x = x*can greatly simplify the computation of DTFS from the coefficients. Let x[n] have a DTFS with coefficients xk = cos(πk/4)+ sin(3πk/4). Note that X are real-valued, but not a symmetric function of index k. (a) Explain why x[n] has period No = 8. (d) Compute the average powers in the time and frequency domains. Confirm that they agree.
The goal of this problem is to show how the conjugate symmetry relation x = x*can greatly simplify the computation of DTFS from the coefficients. Let x[n] have a DTFS with coefficients xk = cos(πk/4)+ sin(3πk/4). Note that X are real-valued, but not a symmetric function of index k. (a) Explain why x[n] has period No = 8. (d) Compute the average powers in the time and frequency domains. Confirm that they agree.
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![The goal of this problem is to show how the conjugate symmetry relation x = x*can greatly simplify the computation of DTFS
from the coefficients.
Let x[n] have a DTFS with coefficients
xk = cos(πk/4)+ sin(3πk/4).
Note that X are real-valued, but not a symmetric function of index k.
(a) Explain why x[n] has period No = 8.
(d) Compute the average powers in the time and frequency domains. Confirm that they agree.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F49c16ca5-b88f-43a3-920e-4b4f8a855675%2Fcb770a6a-43a4-44d3-94a5-269bcb211bba%2Fx96xxs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The goal of this problem is to show how the conjugate symmetry relation x = x*can greatly simplify the computation of DTFS
from the coefficients.
Let x[n] have a DTFS with coefficients
xk = cos(πk/4)+ sin(3πk/4).
Note that X are real-valued, but not a symmetric function of index k.
(a) Explain why x[n] has period No = 8.
(d) Compute the average powers in the time and frequency domains. Confirm that they agree.
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