(50 pts.) In the Capacitive Displacement Sensor project that you are working on in the lab, the capacitance of the transducer cannot be measured directly with a multimeter. We find the capacitance using the frequency of a square wave from an oscillating circuit with the following formula. C = 1.44/[ƒ (R1+2R2)] where fis the measured frequency. R1 and R2 are two resistances in the oscillating circuit. Assuming the following f=3kHZ; R]=1 MQ; R2=2MQ; the error introduce by each component is: ef= 0.001; RI=0.002; R2=0.005. Using error comination analysis method to find the overall fractional error of the indirectly measured C. (hint: Use the absolute fractional error method or SRSS method.)
(50 pts.) In the Capacitive Displacement Sensor project that you are working on in the lab, the capacitance of the transducer cannot be measured directly with a multimeter. We find the capacitance using the frequency of a square wave from an oscillating circuit with the following formula. C = 1.44/[ƒ (R1+2R2)] where fis the measured frequency. R1 and R2 are two resistances in the oscillating circuit. Assuming the following f=3kHZ; R]=1 MQ; R2=2MQ; the error introduce by each component is: ef= 0.001; RI=0.002; R2=0.005. Using error comination analysis method to find the overall fractional error of the indirectly measured C. (hint: Use the absolute fractional error method or SRSS method.)
Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter8: Basic Electric Motors
Section: Chapter Questions
Problem 25RQ: List the five capacitor replacement rules.
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Question
![(50 pts.) In the Capacitive Displacement Sensor project that you are working on in the lab, the
capacitance of the transducer cannot be measured directly with a multimeter. We find the
capacitance using the frequency of a square wave from an oscillating circuit with the following
formula.
C = 1.44/[ƒ (R1+2R2)]
where fis the measured frequency. R1 and R2 are two resistances in the oscillating circuit.
Assuming the following f=3kHZ; R]=1 MQ; R2=2MQ; the error introduce by each component is:
ef= 0.001; RI=0.002; R2=0.005.
Using error comination analysis method to find the overall fractional error of the indirectly
measured C.
(hint: Use the absolute fractional error method or SRSS method.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc10cce41-ef51-4545-a724-9736e236d3b7%2Fc39a3192-658a-4998-ba2b-651e2b97d4e9%2Fsnbpwe8_processed.png&w=3840&q=75)
Transcribed Image Text:(50 pts.) In the Capacitive Displacement Sensor project that you are working on in the lab, the
capacitance of the transducer cannot be measured directly with a multimeter. We find the
capacitance using the frequency of a square wave from an oscillating circuit with the following
formula.
C = 1.44/[ƒ (R1+2R2)]
where fis the measured frequency. R1 and R2 are two resistances in the oscillating circuit.
Assuming the following f=3kHZ; R]=1 MQ; R2=2MQ; the error introduce by each component is:
ef= 0.001; RI=0.002; R2=0.005.
Using error comination analysis method to find the overall fractional error of the indirectly
measured C.
(hint: Use the absolute fractional error method or SRSS method.)
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