(50 pts.) In the Capacitive Displacement Sensor project that you are working on in the lab, the capacitance of the transducer cannot be measured directly with a multimeter. We find the capacitance using the frequency of a square wave from an oscillating circuit with the following formula. C = 1.44/[ƒ (R1+2R2)] where fis the measured frequency. R1 and R2 are two resistances in the oscillating circuit. Assuming the following f=3kHZ; R]=1 MQ; R2=2MQ; the error introduce by each component is: ef= 0.001; RI=0.002; R2=0.005. Using error comination analysis method to find the overall fractional error of the indirectly measured C. (hint: Use the absolute fractional error method or SRSS method.)

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter8: Basic Electric Motors
Section: Chapter Questions
Problem 25RQ: List the five capacitor replacement rules.
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(50 pts.) In the Capacitive Displacement Sensor project that you are working on in the lab, the
capacitance of the transducer cannot be measured directly with a multimeter. We find the
capacitance using the frequency of a square wave from an oscillating circuit with the following
formula.
C = 1.44/[ƒ (R1+2R2)]
where fis the measured frequency. R1 and R2 are two resistances in the oscillating circuit.
Assuming the following f=3kHZ; R]=1 MQ; R2=2MQ; the error introduce by each component is:
ef= 0.001; RI=0.002; R2=0.005.
Using error comination analysis method to find the overall fractional error of the indirectly
measured C.
(hint: Use the absolute fractional error method or SRSS method.)
Transcribed Image Text:(50 pts.) In the Capacitive Displacement Sensor project that you are working on in the lab, the capacitance of the transducer cannot be measured directly with a multimeter. We find the capacitance using the frequency of a square wave from an oscillating circuit with the following formula. C = 1.44/[ƒ (R1+2R2)] where fis the measured frequency. R1 and R2 are two resistances in the oscillating circuit. Assuming the following f=3kHZ; R]=1 MQ; R2=2MQ; the error introduce by each component is: ef= 0.001; RI=0.002; R2=0.005. Using error comination analysis method to find the overall fractional error of the indirectly measured C. (hint: Use the absolute fractional error method or SRSS method.)
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