3.2-4 Since 3e-j(2πfot+0) 3ej(2 fot+0) - 3 sin (2 fot+0) = 2j 38 (f+fo) e- 35 (f- fo) eje 2ejT/2 + 3e-j2fote-je-3j2 foteje 2j 38 (f - fo) e² = 3³½ [8 (f + fo) e −50−j«/² + 8 (ƒ − ƒo) ej®+j=/2] 2e-j/2 The Fourier transform is sketched in Fig. S3.2-4. 3.2-4 Sketch the Fourier transform of signal -3 sin (2л fot+0). Hint: Use Euler's formula to express sin (2лfot + 0) in terms of exponentials.
3.2-4 Since 3e-j(2πfot+0) 3ej(2 fot+0) - 3 sin (2 fot+0) = 2j 38 (f+fo) e- 35 (f- fo) eje 2ejT/2 + 3e-j2fote-je-3j2 foteje 2j 38 (f - fo) e² = 3³½ [8 (f + fo) e −50−j«/² + 8 (ƒ − ƒo) ej®+j=/2] 2e-j/2 The Fourier transform is sketched in Fig. S3.2-4. 3.2-4 Sketch the Fourier transform of signal -3 sin (2л fot+0). Hint: Use Euler's formula to express sin (2лfot + 0) in terms of exponentials.
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![3.2-4 Since
3e-j(2πfot+0)
3ej(2 fot+0)
- 3 sin (2 fot+0)
=
2j
38 (f+fo) e- 35 (f- fo) eje
2ejT/2
+
3e-j2fote-je-3j2 foteje
2j
38 (f - fo) e² = 3³½ [8 (f + fo) e −50−j«/² + 8 (ƒ − ƒo) ej®+j=/2]
2e-j/2
The Fourier transform is sketched in Fig. S3.2-4.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5b55a0fb-5dff-4587-97c0-c3ec381e9c7e%2F7d8d5194-5de9-47c7-ad4a-c4531497bbe0%2F3migp6_processed.png&w=3840&q=75)
Transcribed Image Text:3.2-4 Since
3e-j(2πfot+0)
3ej(2 fot+0)
- 3 sin (2 fot+0)
=
2j
38 (f+fo) e- 35 (f- fo) eje
2ejT/2
+
3e-j2fote-je-3j2 foteje
2j
38 (f - fo) e² = 3³½ [8 (f + fo) e −50−j«/² + 8 (ƒ − ƒo) ej®+j=/2]
2e-j/2
The Fourier transform is sketched in Fig. S3.2-4.

Transcribed Image Text:3.2-4 Sketch the Fourier transform of signal -3 sin (2л fot+0).
Hint: Use Euler's formula to express sin (2лfot + 0) in terms of exponentials.
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