2. Calculate the impedance, current, and voltage values for the circuit shown in the following figure (Fig. 14.53b). R₁ 100 www C₁ 2μF R2 470 520 Hz 100 mH XL = 326.70 Xc1 = 150.03Q Xc2=306.070 RT R1+R2 = 100+ 470 = 5700 Xs = XL-XC1-XC2=326.7-150.03-306.7=-129.40 = 129.402-90° ZT = Sqrt (Xs^2+ R^2= √129.4^2+570^2 = 584.500 8 = tan-1(Xs/R = tan-1(129.4/570)=12.8° I= VS/ZT = 6V/584.5 =10.26mA VR 1*R 10.26* 570 = 5.85VZ0° VL=1* XL = 10.26 * 326.7 = 3.35VZ90° Vc = l * Xc = 10.26 * 456.1 = 4.56V IL = VS/XL = 6V/326.7 = 18.37mA Ic=VS/XC = 6/456.1 =13.16mA ILC IC-IL 13.16-18.37 = -5.21mA IR = VS/R = 6V/570 = 10.52mA IT Sqrt (ILC2+IRC² = √√-5.212 + 570^2 = 569.98mA 0 = tan^-1(ILC/IR = tan^-1(-5.21/10.52)=-26.35° ZT = VS/IT = 6V20° 569.98 =10.530

2. Calculate the impedance, current, and voltage values for the circuit shown in the following figure (Fig. 14.53b). R₁ 100 www C₁ 2μF R2 470 520 Hz 100 mH XL = 326.70 Xc1 = 150.03Q Xc2=306.070 RT R1+R2 = 100+ 470 = 5700 Xs = XL-XC1-XC2=326.7-150.03-306.7=-129.40 = 129.402-90° ZT = Sqrt (Xs^2+ R^2= √129.4^2+570^2 = 584.500 8 = tan-1(Xs/R = tan-1(129.4/570)=12.8° I= VS/ZT = 6V/584.5 =10.26mA VR 1R 10.26 570 = 5.85VZ0° VL=1* XL = 10.26 * 326.7 = 3.35VZ90° Vc = l * Xc = 10.26 * 456.1 = 4.56V IL = VS/XL = 6V/326.7 = 18.37mA Ic=VS/XC = 6/456.1 =13.16mA ILC IC-IL 13.16-18.37 = -5.21mA IR = VS/R = 6V/570 = 10.52mA IT Sqrt (ILC2+IRC² = √√-5.212 + 570^2 = 569.98mA 0 = tan^-1(ILC/IR = tan^-1(-5.21/10.52)=-26.35° ZT = VS/IT = 6V20° 569.98 =10.530

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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