2. Calculate the impedance, current, and voltage values for the circuit shown in the following figure (Fig. 14.53b). R₁ 100 www C₁ 2μF R2 470 520 Hz 100 mH XL = 326.70 Xc1 = 150.03Q Xc2=306.070 RT R1+R2 = 100+ 470 = 5700 Xs = XL-XC1-XC2=326.7-150.03-306.7=-129.40 = 129.402-90° ZT = Sqrt (Xs^2+ R^2= √129.4^2+570^2 = 584.500 8 = tan-1(Xs/R = tan-1(129.4/570)=12.8° I= VS/ZT = 6V/584.5 =10.26mA VR 1*R 10.26* 570 = 5.85VZ0° VL=1* XL = 10.26 * 326.7 = 3.35VZ90° Vc = l * Xc = 10.26 * 456.1 = 4.56V IL = VS/XL = 6V/326.7 = 18.37mA Ic=VS/XC = 6/456.1 =13.16mA ILC IC-IL 13.16-18.37 = -5.21mA IR = VS/R = 6V/570 = 10.52mA IT Sqrt (ILC2+IRC² = √√-5.212 + 570^2 = 569.98mA 0 = tan^-1(ILC/IR = tan^-1(-5.21/10.52)=-26.35° ZT = VS/IT = 6V20° 569.98 =10.530

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Can you help me check my answers for the problem in the image.

2.
Calculate the impedance, current, and voltage values for the circuit shown in the
following figure (Fig. 14.53b).
R₁
100
www
C₁
2μF
R2
470
520 Hz
100 mH
XL = 326.70
Xc1 = 150.03Q
Xc2=306.070
RT
R1+R2 = 100+ 470 = 5700
Xs = XL-XC1-XC2=326.7-150.03-306.7=-129.40 = 129.402-90°
ZT = Sqrt (Xs^2+ R^2= √129.4^2+570^2 = 584.500
8 = tan-1(Xs/R = tan-1(129.4/570)=12.8°
I= VS/ZT = 6V/584.5 =10.26mA
VR 1*R 10.26* 570 = 5.85VZ0°
VL=1* XL = 10.26 * 326.7 = 3.35VZ90°
Vc = l * Xc = 10.26 * 456.1 = 4.56V
IL = VS/XL = 6V/326.7 = 18.37mA
Ic=VS/XC = 6/456.1 =13.16mA
ILC IC-IL 13.16-18.37 = -5.21mA
IR = VS/R = 6V/570 = 10.52mA
IT Sqrt (ILC2+IRC² = √√-5.212 + 570^2 = 569.98mA
0 = tan^-1(ILC/IR = tan^-1(-5.21/10.52)=-26.35°
ZT = VS/IT =
6V20°
569.98
=10.530
Transcribed Image Text:2. Calculate the impedance, current, and voltage values for the circuit shown in the following figure (Fig. 14.53b). R₁ 100 www C₁ 2μF R2 470 520 Hz 100 mH XL = 326.70 Xc1 = 150.03Q Xc2=306.070 RT R1+R2 = 100+ 470 = 5700 Xs = XL-XC1-XC2=326.7-150.03-306.7=-129.40 = 129.402-90° ZT = Sqrt (Xs^2+ R^2= √129.4^2+570^2 = 584.500 8 = tan-1(Xs/R = tan-1(129.4/570)=12.8° I= VS/ZT = 6V/584.5 =10.26mA VR 1*R 10.26* 570 = 5.85VZ0° VL=1* XL = 10.26 * 326.7 = 3.35VZ90° Vc = l * Xc = 10.26 * 456.1 = 4.56V IL = VS/XL = 6V/326.7 = 18.37mA Ic=VS/XC = 6/456.1 =13.16mA ILC IC-IL 13.16-18.37 = -5.21mA IR = VS/R = 6V/570 = 10.52mA IT Sqrt (ILC2+IRC² = √√-5.212 + 570^2 = 569.98mA 0 = tan^-1(ILC/IR = tan^-1(-5.21/10.52)=-26.35° ZT = VS/IT = 6V20° 569.98 =10.530
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