1 ΚΩ ↑ 3 mA 4ΚΩ B C D + + 6 mA 10v 12 V 2 ΚΩ w 4 mA 2ΚΩ E a) At which nodes can KCL be applied? b) Using the variables VA, VB, VC, VD, and VE for the voltages at the nodes: i) write the equations that are based on the voltage sources ii) write equations from applying KCL at single nodes iii) for the system of equations resulting from steps i and ii, write the augmented matrix for inputting into the rref Octave/MatLab function C a Nodes Vo-N=10 -V+V-12 KCL B Eaz 20 Vn-Vo VE-VB -3MA + Ze the VA V 2V 2V₂ = 6 VA-32VE b E43 VEL C VBVC 4-k -3+पोलA V-V ICE 28 E4 CL D Zi Vo-Ve = 6 HK V-V=24 ES KCLE: L = VE-VB 22 VE-Vo + + पJA -V₂HVE = 8 18 Summary of System of V=10 = VA 3VB + 2 VE 6 VB - V=24 V D VE = 8 Eat Solving using Matries VA VB th C Up VC 2 O 0 0 -3 T + 0 0 10 0 12 D 0 -1 O 0 0 30- 2 b 24 8

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Ths incorrect in my problem are identification of single nodes (for KCL) or single loops (for KVL) that can yield equations. Writes equations from KCL or KVL. Demonstrated ability to solve a system of equation using matrices and the rref function on MatLab/Octave. How to check simulate circuit and use the simulation to check answers from analysis.

1 ΚΩ
↑ 3 mA
4ΚΩ
B
C
D
+
+
6 mA
10v
12 V
2 ΚΩ
w
4 mA
2ΚΩ
E
a) At which nodes can KCL be applied?
b) Using the variables VA, VB, VC, VD, and VE for the voltages at the nodes:
i) write the equations that are based on the voltage sources
ii) write equations from applying KCL at single nodes
iii) for the system of equations resulting from steps i and ii, write the augmented
matrix for inputting into the rref Octave/MatLab function
Transcribed Image Text:1 ΚΩ ↑ 3 mA 4ΚΩ B C D + + 6 mA 10v 12 V 2 ΚΩ w 4 mA 2ΚΩ E a) At which nodes can KCL be applied? b) Using the variables VA, VB, VC, VD, and VE for the voltages at the nodes: i) write the equations that are based on the voltage sources ii) write equations from applying KCL at single nodes iii) for the system of equations resulting from steps i and ii, write the augmented matrix for inputting into the rref Octave/MatLab function
C
a
Nodes
Vo-N=10
-V+V-12
KCL B
Eaz
20
Vn-Vo
VE-VB
-3MA
+
Ze
the
VA V 2V 2V₂ = 6
VA-32VE
b
E43
VEL C
VBVC
4-k
-3+पोलA
V-V
ICE
28
E4
CL D
Zi
Vo-Ve
= 6
HK
V-V=24
ES
KCLE:
L = VE-VB
22
VE-Vo
+
+ पJA
-V₂HVE = 8
18
Summary of System of
V=10
=
VA
3VB + 2 VE 6
VB
-
V=24
V
D
VE
= 8
Eat
Solving
using Matries
VA
VB
th
C
Up
VC
2
O
0 0
-3
T
+
0
0
10
0
12
D
0
-1
O
0
0
30-
2
b
24
8
Transcribed Image Text:C a Nodes Vo-N=10 -V+V-12 KCL B Eaz 20 Vn-Vo VE-VB -3MA + Ze the VA V 2V 2V₂ = 6 VA-32VE b E43 VEL C VBVC 4-k -3+पोलA V-V ICE 28 E4 CL D Zi Vo-Ve = 6 HK V-V=24 ES KCLE: L = VE-VB 22 VE-Vo + + पJA -V₂HVE = 8 18 Summary of System of V=10 = VA 3VB + 2 VE 6 VB - V=24 V D VE = 8 Eat Solving using Matries VA VB th C Up VC 2 O 0 0 -3 T + 0 0 10 0 12 D 0 -1 O 0 0 30- 2 b 24 8
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