USE ARBITRARY VALUE Sel AND EQUATE LHS = RHS 2 соп k2 +13 S=1 → I + (+ 2f Wn + w n² 1+2gwn +wy² (LHS 2 RHS) Wh = 1+2 fwn+wn + k₂+ 13 Ch4c Underdamped sys Page 5 (EQ.1) 0 = 4+2 Jwn + k₂+k3 || < | - - S (EQ. 2) 2 Wn² 1-2jWn+Wx2 -wh² = 1 + 2 gwn-win-k₂+k3 -1+2jWn- 0 = и -*2+13 + 1-21W4+442 2% 13 -1+2JWn - k2+13 SOLVE SYSTEM OF (EQ.1) & (FO.2) FOR 12.11 *2=-1 13=-2fwn
USE ARBITRARY VALUE Sel AND EQUATE LHS = RHS 2 соп k2 +13 S=1 → I + (+ 2f Wn + w n² 1+2gwn +wy² (LHS 2 RHS) Wh = 1+2 fwn+wn + k₂+ 13 Ch4c Underdamped sys Page 5 (EQ.1) 0 = 4+2 Jwn + k₂+k3 || < | - - S (EQ. 2) 2 Wn² 1-2jWn+Wx2 -wh² = 1 + 2 gwn-win-k₂+k3 -1+2jWn- 0 = и -*2+13 + 1-21W4+442 2% 13 -1+2JWn - k2+13 SOLVE SYSTEM OF (EQ.1) & (FO.2) FOR 12.11 *2=-1 13=-2fwn
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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solve for k2 and k3 please

Transcribed Image Text:USE ARBITRARY VALUE Sel AND EQUATE
LHS = RHS
2
соп
k2 +13
S=1
→
I
+
(+ 2f Wn + w n²
1+2gwn +wy²
(LHS
2
RHS)
Wh = 1+2 fwn+wn + k₂+ 13
Ch4c Underdamped sys Page 5
(EQ.1)
0 = 4+2 Jwn + k₂+k3
|| < | - - S
(EQ. 2)
2
Wn²
1-2jWn+Wx2
-wh² = 1 + 2 gwn-win-k₂+k3
-1+2jWn-
0 =
и
-*2+13
+
1-21W4+442
2%
13
-1+2JWn - k2+13
SOLVE SYSTEM OF (EQ.1) & (FO.2) FOR 12.11
*2=-1
13=-2fwn
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