+ VPS =5V= R = 2 k www ID - + VD Figure 1.28 A simple diode circuit - EXERCISE PROBLEM Ex 1.9: (a) Consider the circuit shown in Figure 1.28. Let Vps = 8V and Vy = 0.7 V, Assume rf = 0. Calculate the value of R such that I = 1.20 mA. (b) If Vps is reduced to 4 V and R is changed to 3.5 ks2, determine the power dis- sipated in the diode. (Ans. (a) 6.08 ks, (b) 0.66 mW).
+ VPS =5V= R = 2 k www ID - + VD Figure 1.28 A simple diode circuit - EXERCISE PROBLEM Ex 1.9: (a) Consider the circuit shown in Figure 1.28. Let Vps = 8V and Vy = 0.7 V, Assume rf = 0. Calculate the value of R such that I = 1.20 mA. (b) If Vps is reduced to 4 V and R is changed to 3.5 ks2, determine the power dis- sipated in the diode. (Ans. (a) 6.08 ks, (b) 0.66 mW).
Chapter59: Motor Startup And Troubleshooting Basics
Section: Chapter Questions
Problem 12SQ: How is a solid-state diode tested? Explain.
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Transcribed Image Text:+
VPS =5V=
R = 2 k
www
ID
-
+
VD
Figure 1.28 A simple diode
circuit
-
Transcribed Image Text:EXERCISE PROBLEM
Ex 1.9: (a) Consider the circuit shown in Figure 1.28. Let Vps = 8V and
Vy = 0.7 V, Assume rf = 0. Calculate the value of R such that I = 1.20 mA.
(b) If Vps is reduced to 4 V and R is changed to 3.5 ks2, determine the power dis-
sipated in the diode. (Ans. (a) 6.08 ks, (b) 0.66 mW).
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