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Ex 3.4: The transistor in Figure 3.26(a) has parameters VTP = -0.6 V and Kp = 0.2 mA/V². The circuit is biased at VDD = 3.3 V. Assume R₁|| R2 = 300 k. De- sign the circuit such that IDQ = 0.5 mA and VSDQ = 2.0 V. (Ans. R₁ = 885 kn, R2 454 ks, RD = 2.6 ks) R₁₁ VG ww R₂ +VDD www VSG + RD (a) + ID VSD D

Ex 3.4: The transistor in Figure 3.26(a) has parameters VTP = -0.6 V and Kp = 0.2 mA/V². The circuit is biased at VDD = 3.3 V. Assume R₁|| R2 = 300 k. De- sign the circuit such that IDQ = 0.5 mA and VSDQ = 2.0 V. (Ans. R₁ = 885 kn, R2 454 ks, RD = 2.6 ks) R₁₁ VG ww R₂ +VDD www VSG + RD (a) + ID VSD D

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Ex 3.4: The transistor in Figure 3.26(a) has parameters VTP = -0.6 V and Kp = 0.2 mA/V². The circuit is biased at VDD = 3.3 V. Assume R₁|| R2 = 300 k. De- sign the circuit such that IDQ = 0.5 mA and VSDQ = 2.0 V. (Ans. R₁ = 885 kn, R2 454 ks, RD = 2.6 ks)
Transcribed Image Text:Ex 3.4: The transistor in Figure 3.26(a) has parameters VTP = -0.6 V and Kp = 0.2 mA/V². The circuit is biased at VDD = 3.3 V. Assume R₁|| R2 = 300 k. De- sign the circuit such that IDQ = 0.5 mA and VSDQ = 2.0 V. (Ans. R₁ = 885 kn, R2 454 ks, RD = 2.6 ks)
R₁₁ VG ww R₂ +VDD www VSG + RD (a) + ID VSD D
Transcribed Image Text:R₁₁ VG ww R₂ +VDD www VSG + RD (a) + ID VSD D
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