please show work. i will give your work a thumbs up 7. Consider the oscilloscope screen shot below: 500MV AFG Sine 4.00ps 1.0000 Vpp ¥0.000000 1 5.000S/1 IM points 100.006H 0.00 V As shown the Volt / Div - 500mV per division, Time Base - 4.00 us per division, and Frequency is 100 KHz: a) Determine the peak-to-peak voltage (Vpp) and half-cycle average voltage (Vave). b) Determine the peak-voltage (Vpk) and root-mean-square voltage (Vrms). c) What is the period (T) of the 1MHZ signal?

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.