I need a handwritten solution from the expert, along with proof of the answer ImU 0.5 μF Rses C₁ loke F JDD 120v 20347452 gm=2mS 2.2KS RL гме Cgd=2pF, Cgs=4PF Bw?
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- Solve step by step. Please solve fast.3 A peak rectifier (peak tollower) Cir cuit is gian below. Vs is a GOH3 Sinuscidal Vollge with peak value Upz50V. 50V. The load resistance R= Sk . Find the Vallke of the capacitance C Such that the peak- to-peak ripple 2 volts. (idenl diede) Voltage Vr VsPlease help prove the 3 equations in the second attached image.
- FAIRCHILD Discrete POWER & Signal Technologies SEMICONDUCTOR ru 1N4001 - 1N4007 Features • Low torward voltage drop. 10 a14 * High aurge eurrent cepablity. 0.160 4.06) DO 41 COLOR BAND DGNOTEs CAT-Cos 1.0 Ampere General Purpose Rectifiers Absolute Maximum Ratings T-26*Cuness atnerwioe rated Symbol Parameter Value Units Average Recttied Current 1.0 375" lead length a TA - 75°C Tsargei Peak Forward Surge Current 8.3 ms single halr-sine-wave Superimposed on rated load JEDEC method) 30 A Pa Total Device Dissipetion 2.5 20 Derste above 25°C Ra Tag Thermal Resistence, Junction to Amblent 5D Storage Temperature Range 55 to +175 -55 to +150 Operating Junetion Temperature PC "These rarings are imithg valuee above whien the serviceatity or any semiconductor device may te impaired. Electrical Characteristics T-20'Cunieas ofherwise roted Parameter Device Units 4001 4002 4003 4004 4005 4006 4007 Peak Repetitive Reverse Vellage Maximum RME votage DC Reverse Voltage Maximum Reverse Current @ rated VR…Q1 a. Consider you have to choose b/w the Full-Wave Bridge Rectifier (FWBR) & Center-Tapped Full Wave Rectifier (CT-FWR) in one of your semester Lab projects. (1) Discuss the advantages of FWBR over CT-FWR which will justify, why to select the FWBR.How do I get to the answers Provided? Can you show in steps? Thank you
- Solve this ASAP1) Diode half-wave rectifier a) Consider the half-wave rectified sinewave voltage waveform at the right. What is the DC voltage and RMS voltage in terms of Vpeak? Remember: Vp peak ann T/2 1 Vay = DC = v(0)de avg T Sv(t)dt and V = Hve v² (t)dt TConsider the figure shown below. The MPT32 is a diac with a breakover voltage of 32 V. a) b) c) If the triac has a trigger voltage of 0.7 V, What must be the capacitor voltage that triggers the triac? If the triac in the figure shown below has 1 V across it when it is conducting, what is the maximum current through the 500 resistor? What must be the value of the source to start turning off the triac? +50V 7 -50V 50ΚΩ 1kΩ W 1 uF 500 Ω W MPT32 Triac IT.= 15 mA IH= 10 mA