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Froblem 2: Assume the capacitor is initially discharged with v-(0) = 0V. Sketch the capacitor voltage Vc(t) and capacitor current ic(t) of the full-wave rectifier circuit shown below with C = 1µF assuming identical germanium diodes. Hint: The slope of the line in the triangle waveform may be used to determine the point in time that vi(t) = 2Vx- %3D v:(t) D1 D2 6V OFF v;(t) 0.2 0.6 t [s] - ict -6V-- D3 D4 Cvc(t) C OFF+ | OV for t < Os Answers: tstart = 0.02s, Vpeak = 5.4V, vc(t) = {30t – 0.6V for 0.02s 0.2s %3D 5.4V ic ic(t) = {30µA 0.02s

Froblem 2: Assume the capacitor is initially discharged with v-(0) = 0V. Sketch the capacitor voltage Vc(t) and capacitor current ic(t) of the full-wave rectifier circuit shown below with C = 1µF assuming identical germanium diodes. Hint: The slope of the line in the triangle waveform may be used to determine the point in time that vi(t) = 2Vx- %3D v:(t) D1 D2 6V OFF v;(t) 0.2 0.6 t [s] - ict -6V-- D3 D4 Cvc(t) C OFF+ | OV for t < Os Answers: tstart = 0.02s, Vpeak = 5.4V, vc(t) = {30t – 0.6V for 0.02s 0.2s %3D 5.4V ic ic(t) = {30µA 0.02s

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**Problem 2:** Assume the capacitor is initially discharged with \( v_c(0) = 0V \). Sketch the capacitor voltage \( v_c(t) \) and capacitor current \( i_c(t) \) of the full-wave rectifier circuit shown below with \( C = 1\mu F \) assuming identical germanium diodes. **Hint:** The slope of the line in the triangle waveform may be used to determine the point in time that \( v_c(t) = 2V \). --- **Circuit Diagram:** - A full-wave rectifier circuit is shown with four diodes (\(D_1, D_2, D_3, D_4\)) arranged in a bridge configuration. - The input voltage \( v_i(t) \) is applied across the bridge. - A capacitor \( C \) (1μF) is connected across the output, and the output voltage is \( v_c(t) \). - The current through the capacitor is marked as \( i_c(t) \). **Equations:** - \( i_c(t) = \left\{ \begin{array}{ll} 30\mu A & \text{for } 0.02s < t < 0.2s \\ 0 & \text{otherwise} \end{array} \right. \) - \( v_c(t) = \left\{ \begin{array}{ll} 0V & \text{for } t \leq 0s \\ 5.4V - 30t - 0.6V & \text{for } 0.002s < t < 0.2s \\ 5.4V & \text{for } t \geq 0.2s \end{array} \right. \) --- **Graph Description:** The graph shows a triangle waveform representing \( v_i(t) \): - On the horizontal axis, time \( t \) is marked with intervals at 0.2s and 1s. - On the vertical axis, voltage is marked with increments of 6V, ranging from -6V to 6V. - The waveform is a symmetrical triangular wave oscillating between -6V and 6V over a period of 1 second. --- **Answers:** - \( t_{\text{start}} = 0.02s \) - \(
Transcribed Image Text:**Problem 2:** Assume the capacitor is initially discharged with \( v_c(0) = 0V \). Sketch the capacitor voltage \( v_c(t) \) and capacitor current \( i_c(t) \) of the full-wave rectifier circuit shown below with \( C = 1\mu F \) assuming identical germanium diodes. **Hint:** The slope of the line in the triangle waveform may be used to determine the point in time that \( v_c(t) = 2V \). --- **Circuit Diagram:** - A full-wave rectifier circuit is shown with four diodes (\(D_1, D_2, D_3, D_4\)) arranged in a bridge configuration. - The input voltage \( v_i(t) \) is applied across the bridge. - A capacitor \( C \) (1μF) is connected across the output, and the output voltage is \( v_c(t) \). - The current through the capacitor is marked as \( i_c(t) \). **Equations:** - \( i_c(t) = \left\{ \begin{array}{ll} 30\mu A & \text{for } 0.02s < t < 0.2s \\ 0 & \text{otherwise} \end{array} \right. \) - \( v_c(t) = \left\{ \begin{array}{ll} 0V & \text{for } t \leq 0s \\ 5.4V - 30t - 0.6V & \text{for } 0.002s < t < 0.2s \\ 5.4V & \text{for } t \geq 0.2s \end{array} \right. \) --- **Graph Description:** The graph shows a triangle waveform representing \( v_i(t) \): - On the horizontal axis, time \( t \) is marked with intervals at 0.2s and 1s. - On the vertical axis, voltage is marked with increments of 6V, ranging from -6V to 6V. - The waveform is a symmetrical triangular wave oscillating between -6V and 6V over a period of 1 second. --- **Answers:** - \( t_{\text{start}} = 0.02s \) - \(
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