- Simple Electric Circuits a) Connect the 12V DC supply in series with a Single Pole Single Throw (SPST) switch and light bulb as shown in Figure 6 below. Points along the schematic are labeled so you can relate the schematic to the actual components. For example the power supply terminals are A and H. The terminals of a SPST switch are denoted B and C and the terminals of the light bulb, D and E. A single wire or lead connects each of A to B, C to D, E to F, and G to H. Use a voltmeter to measure and record the quantities in Table 1. The double subscript notation makes it easy to identify the path or loop over which voltages are accumulated. For example, the first column of Table 1 identifies the voltages associated with traversing a closed path or loop from H-A-B-C-D-E-F-G-H. The second column identifies the voltages associated with traversing a closed path or loop H-G-F-E-D-C-B-A-H. How is VDE related to VED? How much power is being supplied by the battery and how much is dissipated by the light bulb? Keep this circuit connected until comparisons in step 2a are completed. 1. VAH= 12.10 VBA -0.0030 Vc = -0.03 VDC= -0.004 VED= -12.05 VFE= -0.002 Sum= VGF -0.007 VHG= -0.004 A H Figure 6: Resistive circuit with a light bulb as the resistive element B Table 1: Circuit Measurements for the Circuit of Figure 6. Switch Closed Switch Open VHA = - 12.10 Sum= VAB= 0.0030 VBC= 0.03 VCD= 0.004 VDE= 12.05 VEF= 0.002 ViG= 0.007 VGH = 0.004 How is VED related to VDE? F VBA= VAH = 12.10 VDC= VED= Vcs= -12.10 VFE= D VGF= E R VHG= Sum= How much power (PR) is dissipated by the light bulb? 3. O O 0 O 6 O How much current and power is being supplied by the battery? 2. VHA -12.10 VAB= VBC= VCD= VDE= VEF= VFG= VGH = Sum= O 12.10 Your observations of the sum of the voltage rises around the loop H-G-F-E-D-C-B-A-H: 5. O O O O O Your observations of the sum of the voltages going around the loop H-A-B-C-D-E-F-G-H: 4.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
icon
Related questions
Question

Please help me solve questions 1-5 using the given values found.

1. Simple Electric Circuits
a) Connect the 12V DC supply in series with a Single Pole Single Throw (SPST) switch and
light bulb as shown in Figure 6 below. Points along the schematic are labeled so you can
relate the schematic to the actual components. For example the power supply terminals
are A and H. The terminals of a SPST switch are denoted B and C and the terminals of the
light bulb, D and E. A single wire or lead connects each of A to B, C to D, E to F, and G to
H. Use a voltmeter to measure and record the quantities in Table 1. The double subscript
notation makes it easy to identify the path or loop over which voltages are accumulated.
For example, the first column of Table 1 identifies the voltages associated with traversing
a closed path or loop from H-A-B-C-D-E-F-G-H. The second column identifies the voltages
associated with traversing a closed path or loop H-G-F-E-D-C-B-A-H. How is VDE related to
VED? How much power is being supplied by the battery and how much is dissipated by
the light bulb? Keep this circuit connected until comparisons in step 2a are completed.
1.
3.
VAH = 12.10
VBA= -0.0030
VcB= -0.03
VDC= -0.004
VED= -12.05
VFE-0.002
Sum=
VGF= -0.007
VHG= -0.004
A
H
VFG= 0.007
Sum=
B
VHA= -12.10
VAB= 0.0030
VBC= 0.03
VCD= 0.004
VDE = 12.05
VEF= 0.002
VGH= 0.004
How is VED related to VDE?
G
Figure 6: Resistive circuit with a light bulb as the resistive element
A
Table 1: Circuit Measurements for the Circuit of Figure 6.
Switch Closed
Switch Open
C
F
VBA =
VAH = 12.10
VDC=
VED=
VcB= -|2.|0
VFE=
D
VGF=
E
VHG=
Sum=
How much power (PR) is dissipated by the light bulb?
O
O
How much current and power is being supplied by the battery?
2.
R
O
G
VHA -12.10
VAB=
VBC=
VCD=
VDE=
VEF=
VFG=
VGH=
Sum=
O
12.10
Your observations of the sum of the voltage rises around the loop H-G-F-E-D-C-B-A-H:
5.
O
0
0
Your observations of the sum of the voltages going around the loop H-A-B-C-D-E-F-G-H:
4.
Transcribed Image Text:1. Simple Electric Circuits a) Connect the 12V DC supply in series with a Single Pole Single Throw (SPST) switch and light bulb as shown in Figure 6 below. Points along the schematic are labeled so you can relate the schematic to the actual components. For example the power supply terminals are A and H. The terminals of a SPST switch are denoted B and C and the terminals of the light bulb, D and E. A single wire or lead connects each of A to B, C to D, E to F, and G to H. Use a voltmeter to measure and record the quantities in Table 1. The double subscript notation makes it easy to identify the path or loop over which voltages are accumulated. For example, the first column of Table 1 identifies the voltages associated with traversing a closed path or loop from H-A-B-C-D-E-F-G-H. The second column identifies the voltages associated with traversing a closed path or loop H-G-F-E-D-C-B-A-H. How is VDE related to VED? How much power is being supplied by the battery and how much is dissipated by the light bulb? Keep this circuit connected until comparisons in step 2a are completed. 1. 3. VAH = 12.10 VBA= -0.0030 VcB= -0.03 VDC= -0.004 VED= -12.05 VFE-0.002 Sum= VGF= -0.007 VHG= -0.004 A H VFG= 0.007 Sum= B VHA= -12.10 VAB= 0.0030 VBC= 0.03 VCD= 0.004 VDE = 12.05 VEF= 0.002 VGH= 0.004 How is VED related to VDE? G Figure 6: Resistive circuit with a light bulb as the resistive element A Table 1: Circuit Measurements for the Circuit of Figure 6. Switch Closed Switch Open C F VBA = VAH = 12.10 VDC= VED= VcB= -|2.|0 VFE= D VGF= E VHG= Sum= How much power (PR) is dissipated by the light bulb? O O How much current and power is being supplied by the battery? 2. R O G VHA -12.10 VAB= VBC= VCD= VDE= VEF= VFG= VGH= Sum= O 12.10 Your observations of the sum of the voltage rises around the loop H-G-F-E-D-C-B-A-H: 5. O 0 0 Your observations of the sum of the voltages going around the loop H-A-B-C-D-E-F-G-H: 4.
Expert Solution
steps

Step by step

Solved in 5 steps with 8 images

Blurred answer
Knowledge Booster
Current division Method
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,