Using Nodal analysis, find V1 in Volts if Is = 4.4 A and R = 8.6 Ohms. R wwww Add your answer www 292 ww 6A 12 502 492 www ... Is
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- A clipper circuit based on diodes are simple way to modify waveform in mechatronics. Assume that the two diodes shown in the circuit below are ideal diodes. If the input voltage in the circuit is a 1 kHz sinusoid with peak amplitude of 8V, sketch the Vaue (t). 10 k. 8V 10 kN. D2 RL Vourlt) Vin= Vin(t) Ims D1 6V -8V 4V Page | 1A clipper circuit based on diodes are simple way to modify waveform in mechatronics. Assume that the two diodes shown in the circuit below are ideal diodes. If the input voltage in the circuit is a 1 kHz sinusoid with peak amplitude of 8V, sketch the Va.. (t) 10 kO 8V 10 kO Vin Vin(t) D2 Vout(t) RL Ims D1 6V -8V 4V Page | 1Please show you detailed solution Number 10 A voltage of 250 volts at 50 Hz is impressed on a circuit having a 60-ohm resistor, 35-?F capacitor, and a 0.25-henry inductor in series. Determine power factor. A. 0.979 C. 0.924 B. 0.862 D. 0.707
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- can you solve this question handwritten solution step by step how did we obtain the v0 graph? my question is not a part of a graded assignmentThe current through the diode in the circuit given in the Figure below when Vy = 0.7 V is? ww 8092 12V Select one a. 24.26 mA b. 13.09 mA c. 58.23 mA d. 40.13 mA 40-52 ww 3092 IDIn the circuit of the following figure, the input voltage Vs is 15 volts rms with a frequency of 60 Hz, R equals 150 Ohms and C equals 100,000 Pico Farads. The diodes are Germanium (Vd = 0.2 volts) and the Zener diode is 12 volts. a) The magnitude of the ripple voltage at Cb) The Magnitude of the Peak Inverse Voltage (PIV) for D1 and D2.
- Given the following circuit with VDD= 9.2 V, R=2.3 k2, then the current Iis: Use the CVD model for the diode, with VD = 0.65 V. I VDD a. 0.004000 A O b. 3.717391 A OC. 0 A d. 4.000000 A e. 0.003717 A R + VD -A 20-V-rms 60-Hz ac source is in series with an ideal diode and a 100-Ω resistance. Determine the peak current and PIV for the diode.Q1. a) Figure Q1 is a single phase 2-level voltage source converter (VSC) with a total DC voltage V-1000V. A PWM scheme, by comparing a reference value with a 1kHz triangular waveform, is used to control the switches S₁ and S2, and output 340v at Vo. With the aid of graphs explain how pulse signals for the switches are generated, sketch the output voltage Vo, determine the duty cycle and the modulation index. Va + 2 it Va d + TS₁ V {1+5₂ = Figure Q1 A single phase VSC