Question • Two diodes are connected in series to share a total reverse voltage of VD= 5 KV. Reverse leakage currents of the diodes are Ip1=30 mA and Ip2=35 mA. - Find VD1 and Vp2 for R1=R2=100 k2 Find R, and R, for Vo1=VD2 ER1 Hint: VD1 Is=L+IRI=1+IR2 VD R2 VD2
Question • Two diodes are connected in series to share a total reverse voltage of VD= 5 KV. Reverse leakage currents of the diodes are Ip1=30 mA and Ip2=35 mA. - Find VD1 and Vp2 for R1=R2=100 k2 Find R, and R, for Vo1=VD2 ER1 Hint: VD1 Is=L+IRI=1+IR2 VD R2 VD2
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Transcribed Image Text:Diodes Are Connected In
Series To Share A Total...
21
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• Two diodes are connected in series to share
a total reverse voltage of VD=D 5 KV. Reverse leakage
currents of the diodes are ID1=30 mA and Ip2=35 mA.
- Find Vp1 and Vp2 for R,=R2=100 k2
- Find R, and R2 for VD1=VD2
R1
VD1
Hint:
Is=L,+IRj= I,2+IR2
VD
R2
VD2
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