Problem 2 In the circuit below, use nodal analysis to evaluate 2 Ω + νο 422 202 302 302 502 3 V 5 V (a) The voltage vo (b) The power absorbed by the 4-2 resistor
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A: Summary of ValuesXL=326.73ΩXC1=153.2ΩXC2=306.4ΩXS=173.53ΩXP≈135.18ΩZT≈168.05Ωθ≈53.5∘
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- 2. (60 points total + 20 points extra credit) Here is the Tanabe Sugano diagram for an octahedral inorganic complex: 80 25 70 2F G 21 11111 2F 2 D F 50 E/B 40. *P DPG D AG 30 20 20 110 10 4A2 AE 6A1 6S 0 10 20 +A1, *E 2A1 2E 2A21 271 *T₁ (12*e) 6A1(12³ e²) | 2T₂ (125) 30 40 50 A/B a. (20 points) What is the delectron count of this complex (e. g. d'? Briefly explain your answer.Part B Given the following circuit F1 SW1 SW2 Sw3 SW4 SW5 SW6 BAT1 R1 R2 R3 R4 R5 R6 12 V 12 0 24 0 48 0 00Please answer the questions on the figure!
- Explain this diagram2. Determine the voltage with respect to ground at each point in below. Assume the practical model. Solve and Simulate to compare the result. D1 D2 C R A B D 1.0 kΩ + Vs2 8 V VsI 25 VUsing the three rules for series circuits and Ohm’s law, solve for the missing values. ET 120 V E1 E2 E3 E4 E5 IT I1 I2 I3 I4 I5 RT R1 430 Ω R2 360 Ω R3 750 Ω R4 1000 Ω R5 620 Ω PT P1 P2 P3 P4 P5 ET E1 E2 E3 11 V E4 E5 IT I1 I2 I3 I4 I5 RT R1 R2 R3 R4 R5 PT 0.25 W P1 0.03 W P2 0.0825 W P3 P4 0.045 W P5 0.0375 W ET 340 V E1 44 V E2 94 V E3 60 V E4 40 V E5 IT I1 I2 I3 I4 I5 RT R1 R2 R3 R4 R5 PT P1 P2 P3 P4 P5 0.204 W
- For the circuit below, determine the voltage across resistors R1: The two sources V1 and V2 are cosine voltage sources: V1: Vp = 20 V, 0 = 0°, o = 1250 rad/secs V2: Vp = 12 V, 0 = 45°, o = 1250 rad/secs L1 C1 HH 15u 20mH R2 35 V1 V2 VOFF = 0 VAMPL = 12 FREQ = 198.94 AC = 0 VOFF = 0 VAMPL = 20 FREQ = 198.94 AC = 0 R1 10How would I approach this question? Do I need to use Kirchoff's junction rules or can I just subtract the voltage drop?Please identify the two elements. Choose for the correct answer.
- Using voltage division, find VAB. w 11 Q 18 Q 12 0 V2 12 V VAB 12 Q 70 Select one: Oa. VAB=7.741. O b. None Of them Oc. VAB=12 O d.VAB-4.8 V. Oe. VAB=3.6V.solve for the equivalent resistance, RAB as asimplified numerical value. Visually solve for the equivalent resistance by making simplifications and then redrawing (twice) the circuit.Give me right solution with clear calculations