Q1) A three phase full controlled rectifier is supplied from three phase 230V, 60Hz supply. If the average load current lac-150A and the commutating source inductance L=0.1 mH. (a) Determine the overlap angle (y) when a = 10°,30° and 60° (b) Draw the load voltage for each value of a
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- What is CEMF?A single phase – half wave controlled rectifier with freewheeling diode is supplying a load consistingseries connected a resistor and an inductance from a 70.7V (RMS), 50Hz sinusoidal AC source.The firing delay of the thyristor is 90° and the load values are R=10Ω, L=0.1 H. Define the loadcurrent expression and draw the load current by calculating for first two periods. And calculate theaverage values of the load voltage and current.A three-phase rectifier is supplied by a 173.2-V rms line-to-line 60-Hz source. The RL load is a 100 resistor in series with a 15-mH inductor. Determine THD taking Is1 = 1.35
- A three phase full wave rectifier is shown below along with peak phase voltage Vm-169.7V. The load is purely resistive. The rectifier delivers Ipc = 100 A and the source frequency is 60 Hz. The DC output voltage is %3D VDc=280.7V and the output RMS voltage is equal to VRMS=280.93V. The efficiency, FF and RF are respectively equal to: Secondary D D D, R AD. Z D. D, Select one: O a. 99.83%, 100.08%, 4% O b. 99.83%, 55.08%, 4% O C. 99.83%, 100.08%, 16% O d. 87.83%, 100.08%, 4%A certain unfiltered center-tapped full wave rectifier is powered by a 120 Vrms, 60 Hz power system. The peak value of the output voltage under loaded conditions is 30 V. The capacitance value is 2000 uF, load current of 2A, determine the following: Peak to peak ripple voltage RMŞ ripple voltage 4. а.In the circuit of the following figure, the input voltage Vs is 15 volts rms with a frequency of 60 Hz, R equals 150 Ohms and C equals 100,000 Pico Farads. The diodes are Germanium (Vd = 0.2 volts) and the Zener diode is 12 volts. a) The magnitude of the ripple voltage at Cb) The Magnitude of the Peak Inverse Voltage (PIV) for D1 and D2.
- Single phase diode bridge rectifier is connected to 220 V, 50 Hz supply to feed 5-ohm resistor in series with 10 mH inductor. Calculate and draw the load current during the first two periods of supply voltages waveform.A three phase full wave rectifier is shown below. The input phase voltage peak is Vm=311.128 V. The load is purely resistive of value 52. The DC and RMS output voltages are respectively equal to: Secondary 太D太D,太D, 太D。太De太D, b. Select one: O a. 180V, 240.2V O b. 514.6V, 515.04V O c. 180V, 197.2V O d. 220V, 249.2VQ5. For the following center tapped transformer, show the waveform across each half of the secondary winding and across Ri, when a 100 V peak sine wave is applied to the primarywinding. What is the PIV rating must the diode have? (Use constant voltage drop model for the Silicon diode) IN4001 Ry OV 10k) D IN4001
- A full wave bridge rectifier is supplied from 230V, 50Hz and uses a transformer of turns ration 15:1. It uses load resistance of 50 ohms. Calculate load voltage and ripple voltage. Assume ideal diode and transformer. Assume ripple factor equals to 0.482. a.Load Voltage= 13.8 V; Ripple Voltage=6.652 V b.Load Voltage= 15.6 V; Ripple Voltage=7.611 V c.Load Voltage= 21.3 V; Ripple Voltage=8.410 V d.Load Voltage= 25.1 V; Ripple Voltage=10.442 VPlease respond to two part question in attached image. Please.For the full wave rectifier circuit shown in Figure 1, calculate: 1) The maximum current through the load. 2) The average current through the load. 3) The average voltage across the load. 4) The rms value of the current. 5) The rectification efficiency. Vms = 280V Vin RL= 12ks2 Vrms = 280V Figure 1