8Ω ww 5 mH m 80 V + t=0 50 V 2002 ww 12 Ω Figure #1 For the circuit shown in figure #1, determine the voltage across the 12 ohms resistor 50 ms after opening the switch
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- Zener Diodes: In the following diagram, Iz = 0.5 mA, Vz = 5, rz = 30 ohms. What is Vout? What is the current through D5? Current through D7?A Si solar cell has a short-circuit current of 100 mA and an open-circuit voltage of 0.8 V under full solar illumination. The fill factor is 0.7. What is the maximum power delivered to a load by this cell?R A IOLL 4) 2A A 2a R4 20V a) Find the voltage at point A due to the 20V source only. b) Find the voltage at point A due to the 2A current source only. c) Find the voltage at point A when both are activated.
- What is wrong with this circuit? * R₁ 10 kn - V₁ 24 V 4.790 V R₂2.5 kn RL 1 15 V The zener is open. The zener is shorted or damaged O not enough data O reversed connection of zener diode D₁ 1N4744AThe schematic is step 7For the following circuit, the diodes are silicon with a forward barrier voltage of 0.7-V. Calculate ID, ID2, D3, and VA using the following steps: ↓ +5 V ww R₁ = 5kQ VA D₁ D₂7 IDI R, = 5 kΩ -10 V 11p2 ID3 -5 V D3 VB R3= 5 kQ2 ↓ a) Assume all of the diodes are forward-biased and conducting. Redraw the circuit. Therefore, ideal voltage sources can be substituted for ID₁, D₂ and ID3. What are the values of V₁ and V?
- Please answer all subpart please Asap I will like it please ASAPFigure 2 4. Consider the circuit in Figure 3. D1 is Gallium arsenide and D2 is Silicon, each has a forward resistance of 500. Determine the following: a. The states of D1 and D2. Explain. b. Current 11 through R1 c. Current 12 through R2 d. Current 13 through R3 e. Voltage Vo Liv Hilt R1 1092 V1 12V (+2) V1 D1 1V 50Hz 0° 1 D1 R2 1592 Figure 3 5. Do number 4 again, but this time reverse both the positions of D1 and D2. 6. Consider the circuit in Figure 4. a. Calculate the voltage across R3 during the positive half cycle of the source voltage V1. b. Calculate the voltage across R3 during the negative half cycle of the source voltage V1. c. Sketch the waveform of the voltage across R3. R1 1kQ V2 9V D2 R3 10092 R2 1k92 D2 Vo R3 1k92C -Q (A) 0.25 uF 10V 2uF 4uF (B) Figure 3: 3. In Figure 3 the capacitors were discharged before being connected to the battery. (a) In Figure 3A the net positive charge delivered by the battery is +Q1 to C1 and a net negative charge -[Q2 + Q3] is delivered to C2 and C3 [-Q2 is delivered to C2 and -Q3 to C3]. From conservation of charge[net charge is zero since both the battery and the capacitors have a zero net excess charge] and path independence of the electric field[sum of voltages must add up to zero for a closed path or conservation of energy]: Q1 + (-Q2) + (-Q3) = 0 conservation of charge +%-왕-용 (True, False) = 0 conservation of energy +V - = 0 conservation of energy (b) If (a) is true then the charge Q1, Q2 and Q3 follow from above three equations as C1(C2 + C3) V Q2 = Ci + C2 + C3 C1 C3 Ci + C2 + C3 Q1 = Q3 = V, (True, False) C1 + C2 + C3 (c) In Figure 3A the net positive charge delivered by the battery is Qtot = Q1 = C1(C2+C3) v which implies an equivalent capacitance of Qtot…