For cross 1: Total (N) = 562 %3D n= 4 Expected (E) frequency Total/n = 562/4 = 140.5 Observed (O) Expected (E) (0-E)^2/E Phenotypes Red Eyes /Normal wings White eyes /Normal wings Red eyes/vertical wings White eyes/Vertical wings Total (N) (0-E)^2 367 140.5 51302.25 365.1406 97 140.5 1892.25 13.4680 74 140.5 4422.25 31.4751 24 140.5 13572.25 96.5996 562 Chi-square test statistic (x³) = 506.6833 Chi-square test statistic (x²) = 506.6833

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Give a brief analysis on the following chi-square for cross 1(wild type female × white eyes vestigial wings male) ( write a paragraph or more)

For cross 1:
Total (N) = 562
n =4
Expected (E) frequency = Total/n = 562/4 = 140.5
Observed (0)
Expected (E)
(0-E)^2
(0-E)^2/E
Phenotypes
Red Eyes /Normal wings
White eyes /Normal wings
Red eyes/vertical wings
White eyes/Vertical wings
Total (N)
367
140.5
51302.25
365.1406
97
140.5
1892.25
13.4680
74
140.5
4422.25
31.4751
24
140.5
13572.25
96.5996
562
Chi-square test statistic (x) =
506.6833
Chi-square test statistic (x2) = 506.6833
Transcribed Image Text:For cross 1: Total (N) = 562 n =4 Expected (E) frequency = Total/n = 562/4 = 140.5 Observed (0) Expected (E) (0-E)^2 (0-E)^2/E Phenotypes Red Eyes /Normal wings White eyes /Normal wings Red eyes/vertical wings White eyes/Vertical wings Total (N) 367 140.5 51302.25 365.1406 97 140.5 1892.25 13.4680 74 140.5 4422.25 31.4751 24 140.5 13572.25 96.5996 562 Chi-square test statistic (x) = 506.6833 Chi-square test statistic (x2) = 506.6833
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