The following is the result of a three point cross abc X ABC

Human Anatomy & Physiology (11th Edition)
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### Three Point Cross Result: **abc** x **ABC**

The following data represents the outcome of a three-point genetic cross between the alleles **abc** and **ABC**.

| Phenotype | Frequency |
|-----------|-----------|
| abc       | 100       |
| ABC       | 110       |
| aBC       | 25        |
| Abc       | 30        |
| AbC       | 4         |
| abC       | 27        |
| ABc       | 29        |
| aBc       | 3         |
| **Total** | **328**   |

### Analysis

1. **Parental Types:** The two most frequent classes are abc and ABC with counts of 100 and 110, respectively. 
2. **Single Crossover Types:** These are classes with intermediate frequencies: aBC (25), Abc (30), abC (27), and ABc (29).
3. **Double Crossover Types:** These are the least frequent classes: aBc (3) and AbC (4).

### Question

**20) What is the map distance between a and b?**

(Note: The map distance can be calculated using the formula based on recombination frequencies).

For a detailed calculation, consider the recombination frequencies and apply basic principles of genetic mapping to determine the map distances. In this scenario, you would typically sum the frequencies of the single crossover classes involving the genes 'a' and 'b' and then convert this into a percentage of the total frequency.
Transcribed Image Text:### Three Point Cross Result: **abc** x **ABC** The following data represents the outcome of a three-point genetic cross between the alleles **abc** and **ABC**. | Phenotype | Frequency | |-----------|-----------| | abc | 100 | | ABC | 110 | | aBC | 25 | | Abc | 30 | | AbC | 4 | | abC | 27 | | ABc | 29 | | aBc | 3 | | **Total** | **328** | ### Analysis 1. **Parental Types:** The two most frequent classes are abc and ABC with counts of 100 and 110, respectively. 2. **Single Crossover Types:** These are classes with intermediate frequencies: aBC (25), Abc (30), abC (27), and ABc (29). 3. **Double Crossover Types:** These are the least frequent classes: aBc (3) and AbC (4). ### Question **20) What is the map distance between a and b?** (Note: The map distance can be calculated using the formula based on recombination frequencies). For a detailed calculation, consider the recombination frequencies and apply basic principles of genetic mapping to determine the map distances. In this scenario, you would typically sum the frequencies of the single crossover classes involving the genes 'a' and 'b' and then convert this into a percentage of the total frequency.
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