Find kcat for a reaction in which Vmax is 4 × 10-4 mol-min-1 and the reaction mixturecontains one nanogram of enzyme. The molecular weight of the enzyme is 200,000Da (1 Da = 1 g/mol).2 x 10-13 min-12 x 10-11 min-¹80 min-¹8 x 107 min-¹8 x 10¹0 min-¹

Kcat or the turnover number is the the number of substrate molecules converted into product per…

Answered: Find kcat for a reaction in which Vmax…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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The following data were collected in the study of a new enzyme and an inhibitor of the new enzyme: Vo (nmol/sec) [S] (uM) 1.3 - Inhibitor + Inhibitor 2.50 0.62 2.6 4.00 1.42 6.5 6.30 2.65 13.0 7.60 3.12 26.0 9.00 3.58 What is the Km of the inhibited enzyme reaction?
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Below is kinetic data obtained for an enzyme-catalyzed reaction. The enzyme concentration is fixed at 100 nM. Using a Lineweaver-Burke plot, calculate the kcat value for this reaction. Report your answer to three significant figures in units of 1/sec.
At what substrate concentration would an enzyme with a Km of 0.005M operate at one quarter of its Vmax? What would be the Km for an enzyme if it is operating at 90% of its Vmax when the substrate concentration is 0.01M
Could you explain step by step how to solve this? I'm not sure how to get all the numbers that are shown in the solved answer.
1) Define metabolism and describe the importance of metabolism to life. 2) Calculate the change in free energy (∆G ) for the below reaction and answer the two follow up questions: Gfinal state = 3.4 kcal/ mol and Ginitial state = 10.7 kcal/ mol Recall: ∆G = Gfinal state – Ginitial state a. Is this a spontaneous or non-spontaneous reaction? Explain. b. Is there energy released from this reaction which can be used to do work? Explain. 2) List four conditions which impact an enzymes rate of activity. Explain.
Consider the following chemical equation whose delta(G) = 9kcal/mol: AC + BD ---> AB + CD what are the reactants and what are the products is this reaction spontaneous? How do you know? Is energy released or consumed by this reaction? If an enzyme, which catalyzes this reaction is added, what will happen to delta (G) If this reaction is coupled to another reaction, whose delta(G) is -12 kcal/mol, what will be the net delta(G) value? will the overall reaction be spontaneous
The process of protein decomposition by pepsin enzymes in stomach is assumed and modeled as a batch reactor. If the protein concentration over time is measured as follows: Write the relationship between time (t), protein concentration (CA). Assuming that the enzyme reaction follows Michaelis-Menten kinetics, write the required constant (Vmax, Km), and the initial concentration of the protein is CA0.
The KM of a Michaelis-Menten enzyme for a substrate is 1.0 x 104 M. At a substrate concentration of 0.20 M, v = 43 μmol/min. Calculate the rate of reaction when the substrate concentration is tenfold lower, 0.020M. 43 μmol min rate of reaction → Vmax Км substrate concentration →
The following data were collected in the study of a new enzyme and an inhibitor of the new enzyme: Vo (nmol/sec) [S] (µM). 1.3 - Inhibitor + Inhibitor 2.50 0.62 2.6 4.00 1.42 6.5 6.30 2.65 13.0 7.60 3.12 26.0 9.00 3.58 What is the Vmax of the inhibited enzyme reaction?
Write the balanced reaction catalyzed by phophoenolpyruvate carboxylase (P PC). Remember to add any cofactors, and to draw the structure formulas (a line-bond representation is fine) for the main substrate and product of the reaction.
From a series of flasks with a constant concentration of enzyme the following initial velocities weretaken, they were obtained as a function of the concentration of the substrate.a) Calculate the KM and Vmax kinetic parameters of the three forms (Lineweaver-Burk, Eadie-Hofstee, Dixon).b) Analyze which are the atypical data that cause a low correlation, which can be eliminated and explain youranswer.

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Find kcat for a reaction in which Vmax is 4 x 10-4 mol-min-1 and the reaction mixture contains one nanogram of enzyme. The molecular weight of the enzyme is 200,000 Da (1 Da 1 g/mol). = O2 x 10-13 min-1 2 × 10-11 min-1 80 min-1 8 × 107 min-1 8 x 1010 min-1