Lineweaver Burk plot to determine the Vmax and Km
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
Related questions
Question
How do you use Lineweaver Burk plot to determine the Vmax and Km for both the uninhibited enzyme and the enzyme with “Inhibitor A”?

Transcribed Image Text:Table 4.3
Mean Rate (mm/minute) of ONPG hydrolysis catalyzed by
ß-Galactosidase at various ONPG concentrations with and
without inhibitor. Each mean is the average of 36 replicates.
ONPG
Concentration
(MM)
0
3
5
7.5
10
15
20
30
40
Mean Reaction Rate (mm/minute)
SEM
No
Inhibitor (No Inhibitor)
0.000
0.000
0.007
0.000
0.012
0.001
0.015
0.001
0.020
0.001
0.027
0.001
0.033
0.001
0.045
0.002
0.046
0.001
Inhibitor
A
0.000
0.004
0.006
0.009
0.012
0.017
0.021
0.032
0.034
SEM
(Inhibitor A)
0.000
0.000
0.000
0.001
0.001
0.001
0.001
0.001
0.001
![1/Mean Reaction Rate (1/mm/min)
300
250
200
150
100
50
0
-0.05
0.00
◆no inhibitor
Inhibitor A
0.05
0.10
0.15
0.20
1/[ONPG] (1/mM)
y = 733.66x + 10.919
0.25
y = 390.8x + 10.77
0.30
0.35
Figure 4.4: Lineweaver-Burk plot showing the effect of an inhibitor on hydrolysis
of ONPG by b-galactosidase. Data points are the means of 36 replicates.
0.40](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2e5f5ca1-9c38-413c-af6b-0878d611ceab%2F213f580d-3b63-4df7-9686-f8aa79a576b7%2Fn4qu26i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1/Mean Reaction Rate (1/mm/min)
300
250
200
150
100
50
0
-0.05
0.00
◆no inhibitor
Inhibitor A
0.05
0.10
0.15
0.20
1/[ONPG] (1/mM)
y = 733.66x + 10.919
0.25
y = 390.8x + 10.77
0.30
0.35
Figure 4.4: Lineweaver-Burk plot showing the effect of an inhibitor on hydrolysis
of ONPG by b-galactosidase. Data points are the means of 36 replicates.
0.40
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