Ex. Create an estimated S-N diagram for an aluminum bar and define its equation . what is the corrected fatigue strength at N = 2 #10 cycles ? Out = 310 MPa, the forged bar is 3.81 cm in N=2107 round. The load is fully reversed torsion.
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- Find: approximate yield strength (Sy) of 6061 T6 aluminum sheet LT at room temperature? approximate modulus of elasticity of 250 maraging steel?A bar of steel has the minimum properties Se = 276 MPa, Sy = 413 MPa, and Sut = 551 MPa. The bar is subjected to a steady torsional stress of 103 MPa and an alternating bending stress of 172 MPa. Find the factor of safety guarding against a static failure, and either the factor of safety guarding against a fatigue failure or the expected life of the part. For the fatigue analysis use: (a) Modified Goodman criterion. (b) Gerber criterion. (c) ASME-elliptic criterion.A cylindrical steel bar 8 mm in diameter is loaded 1000 cycles per day with a load of 15560 N. How long until fatigue failure takes place? Note: stress force/area 500 450 400 350 Steel Allby 300 250 200 150 Brass Alloy 100 50 1.00E-07 Cycles to Failure, N 1.00E+04 1.00E+05 1.00E-06 1.00E+08 100E+09 1.00E+10 , The bar should not fatigue. ) The bar will fail in one cycle. ) 100 days ) 1000 days Stress Amplitude, MPa
- A circular bar - shown below, made of AISI 1040 OQT 1300 steel (SU = 600 MPa), is loaded with an axial tensile loading P. Calculate the modified endurance strength (SE) and the modified fatigue strength (SF) for the bar if D = 36 mm, d = 30 mm, and r = 2.4 mm. Use the number of cycles to fracture to be 5 × 105. Assume that the surface finish factor, kf, is 0.85, the size factor, kS, is 0.85, and the notch sensitivity factor, qn, is 0.75. Use the following equations if needed,Please Follow this Properly, I Like your answer Structure, Accuracy, Concept, Please No submit Handwriting.Q6:1f the rod fracture at 35% elongation find the percentage difference between engineering and true stress at fracture point?
- What is the approximate yield strength of 250 maraging steel at room temperature? (No need to do a 0.2% offset, just estimate from the graph)ou A bar of steel has the minimum properties S,- 276 MPa, S,-413 MPa, and Su= 551 MPa. The bar is subjected to a steady torsional stress (r m) of 103 MPa and an alternating bending stress (oa ) of 172 MPa. Find the factor of safety guarding against a static failure, and either the factor of safety guarding against a fatigue failure or the expected life of the part. For the fatigue analysis use: (a) Modified Goodman criterion. (b) Gerber criterion. (c) ASME-elliptic criterion note // assume the Kr and Ks equal 1a) A bar of normalized AISI 4130 is subjected to a steady torsional stress of 103 MPa, an alternating torsional stress of 69 MPa, and alternating bending stress of 83 MPa. It has an endurance limit of 276 MPa. Using Gerber and ASME-elliptic criteria, find the safety factors guarding against a fatigue failure and the expected life of the part. Analyse your results. b) A bar of 25 mm diameter cold-drawn SAE 1045 steel is loaded in rotating bending. Determine its endurance limit or strength.
- please help solve and explain and include FBD pleaseFor a number of points during a tension test on Man-Ten steel, engineering stress and strain data are given in Table. Also given are minimum diameters measured in the necked region in the latter portions of the test. The initial diameter was 6.32 mm. (a) Determine the Young’s modulus; (b) Determine the true stress and strain throughout; (c) Calculate the true plastic strain for the beyond yielding.A steel rotating-beam test specimen has an ultimate strength, Sut, of 120 kpsi. Estimate the life of the specimen if it is tested at a completely reversed stress amplitude, Orev, of 74 kpsi. Take the value of the fatigue strength fraction, f, from Fig. 6-23. The life of the specimen is cycles.