PROBLEM 7. A built-up section is composed of two (2) channels and a baseplate. To determine its strengthagainst loads, the following should be calculated (note: moment of inertia should be about centroidal x andy axes):[6] (ANSWER: 139.398 mm)[7] (ANSWER: 291.637 mm)[8] Tx (ANSWER: 360.354x10^6 mm^4)[9] Ty (ANSWER: 109.106x10^6 mm^4)[10] rx (ANSWER: 135.940 mm)C380X74flange-BP305x20-C310X30.8webtw-tfbfPProperties of channel (C310x30.8):A = 3920 mm²; d=305 mm; by = 74.7 mm ;tw = 7.16 mm; t = 12.7 mm; x = 17.7 mm ;Ix = 53.7 x 106 mm²; ly = 1.61 x 106 mm²Properties of channel (C380x74):||4=9480 mm²; d=381 mm; by = 94.5 mm;tw = 18.2 mm; t = 16.5 mm; x = 20.3 mm ;Ix = 168 x 10 mm²; Iy = 4.58 x 106 mm²x105.2500

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Answered: PROBLEM 7. A built-up section is…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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A built-up section is composed of two (2) channels and a baseplate. To determine its strength against loads, the following should be calculated (note: moment of inertia should be about centroidal x and y axes): [6] (ANSWER: 139.398 mm) [7] (ANSWER: 291.637 mm) Properties of channel (C310x30.8): = A 3920 mm²; d=305 mm; by 74.7 mm ; tw = 7.16mm; t = 12.7 mm; x = 17.7 mm ; Ix=53.7 x 10 mm²; ly = 1.61 x 106 mm² Properties of channel (C380x74): 4 = 9480 mm²; d=381 mm; by = 94.5 mm ; tw = 18.2 mm; t = 16.5 mm; x = 20.3 mm; Ix=168 x 10 mm²; Iy = 4.58 x 106 mm² y C380X74 flange -BP305x20 -C310X30.8 web X 105.2500- tw- tf # bf P
A built-up section is composed of two (2) channels and a baseplate. To determine its strength against loads, the following should be calculated (note: moment of inertia should be about centroidal x and y axes): [8] Tx (ANSWER: 360.354x10^6 mm^4) [9] Ty (ANSWER: 109.106x10^6 mm^4)| [10] rx (ANSWER: 135.940 mm) Properties of channel (C310x30.8): = A = 3920 mm²; d=305 mm; by 74.7 mm; tw = 7.16mm; t = 12.7 mm; x = 17.7 mm ; 1x = 53.7 x 10 mm²; Iy = 1.61 x 106 mm² Properties of channel (C380x74): A = 9480 mm²; d= 381 mm; b = 94.5 mm ; tw = 18.2 mm; t = 16.5 mm; x = 20.3 mm; Ix=168 x 106 mm²; ly = 4.58 x 106 mm² y flange BP305x20 C310X30.8 web 105.2500- -C380X74 tw- tf bf
Q5
QUESTION 2 Question 2 A cross-section of a beam is shown in Figure Q2. If the shear force in this section is V = 125 KN, determine the value and the location of the maximum shear stress in the section. In Figure Q2, a = 30 mm and the origin of the coordinate system is at centroid of the cross section. 7 y= Z= A a AY S= 20 4a mm; mm; O Figure Q2 Answer The vertical coordinate (y-coordinate; the y-axis serves as the axis of symmetry of the cross- section.) and horizontal coordinate (z-coordinate) of the location where the maximum shear stress occurs in the section are ← a The vertical distance from the location where the maximum shear stress occurs in the section to the bottom side (AB cross section can be calculated as Distance = mm (units: mm) 3a Second moment of area The second moment of area employed in the equation to calculate maximum shear stress can be calculated as I₂ = a (units: mm²) Shear stress The second moment of area employed in the equation to calculate maximum shear…
3) A point mass is attached to one end of a beam levered against a spike which acts as the pivot. The point mass weighs 250N and the beam has a uniform mass of 10kg and is 8m long. Parts a and b Part c Fapplied 3 of 6mov 1m 8m Krist 0 = 60° Scale 250 N Scale a. If a scale placed beneath the point mass reads 250N, what is the magnitude and direction for the force at the pivot point? Direction: North, 90° from x-axis Magnitude to k* 250N = 2500 N b. For the same scenario, how far must the pivot point be located relative to the left edge of the beam? (Hint, both the boxes weight and the force from the scale act at the farthest right edge of the beam.) www.acta 0672nos onl c. The pivot is then moved to be 6m from the left edge of the beam which now makes a 60 angle with the floor. How much downward force would be needed at the left-most edge of the beam to reduce the reading on the scale to zero? (Hint: the beam is still in static eq. when the scale reads zero.)
Please Provide correct solution, correct Method. No Missing steps / calculations. No Handwriting please
V) Determine the magnitude of y-component reaction (Ry) at journal B (answer in unit Newton, with two decimal places). vi) Determine the magnitude of z-component reaction (Rz) at journal B (answer in unit Newton, with two decimal places). vii)
R10 O Reaction Points 84 cm Loading Points Area = 1594 cm^2 W/2 W/2 54 cm L1=27 cm Figure 2. Skateboard dimensions and loading conditions. Loading conditions Weight of a skateboarder, W 90 kg Load case: Calculate Bending and twisting moment, Ms, Mxy Use Tsai-Wu failure criterion for selection of relevant laminate design. Specifically, the core materials failure is free of any failure; therefore, it can be analyzed based on maximum strain failure criterion with =0.1. D3D20 cm
Consider the beam shown in (Eigure 1). Suppose that w=360 N/m Figure Ⓒ1of1> 1 of 1 -3m Express your answer to three significant figures and include the appropriate units ▸ View Available Hint(s) F = 675 N Previous Answers ✓ Correct Correct answer is shown. Your answer 674 N was either rounded differently or used a different number of significant figures than required for this part Here we learn how to find a reaction force on a beam at a rocker on an inclined surface caused by an external distributed loading, using equations of equilibrium Part B Determine the and y components of reaction at I using scalar notation Express your answers in newtons to three significant figures separated by a comma. ▸ View Available Hint(s) VAX vec B..B,- 405,540 Submit Previous Answers Incorrect; Try Again; 3 attempts remaining N
This is a Important Problem, Please solve carefully Include all the steps (diagram, formula) Handwritten Solution Recommended
The person who answered this previously used sin and cos-please use geometry for example 3,4,5 triangles things of that nature. Thanks
Could I get this question explained step for step thanks

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