PROBLEM 7. A built-up section is composed of two (2) channels and a baseplate. To determine its strengthagainst loads, the following should be calculated (note: moment of inertia should be about centroidal x andy axes):[6] (ANSWER: 139.398 mm)[7] (ANSWER: 291.637 mm)[8] Tx (ANSWER: 360.354x10^6 mm^4)[9] Ty (ANSWER: 109.106x10^6 mm^4)[10] rx (ANSWER: 135.940 mm)C380X74flange-BP305x20-C310X30.8webtw-tfbfPProperties of channel (C310x30.8):A = 3920 mm²; d=305 mm; by = 74.7 mm ;tw = 7.16 mm; t = 12.7 mm; x = 17.7 mm ;Ix = 53.7 x 106 mm²; ly = 1.61 x 106 mm²Properties of channel (C380x74):||4=9480 mm²; d=381 mm; by = 94.5 mm;tw = 18.2 mm; t = 16.5 mm; x = 20.3 mm ;Ix = 168 x 10 mm²; Iy = 4.58 x 106 mm²x105.2500

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Answered: PROBLEM 7. A built-up section is…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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A built-up section is composed of two (2) channels and a baseplate. To determine its strength against loads, the following should be calculated (note: moment of inertia should be about centroidal x and y axes): [6] (ANSWER: 139.398 mm) [7] (ANSWER: 291.637 mm) Properties of channel (C310x30.8): = A 3920 mm²; d=305 mm; by 74.7 mm ; tw = 7.16mm; t = 12.7 mm; x = 17.7 mm ; Ix=53.7 x 10 mm²; ly = 1.61 x 106 mm² Properties of channel (C380x74): 4 = 9480 mm²; d=381 mm; by = 94.5 mm ; tw = 18.2 mm; t = 16.5 mm; x = 20.3 mm; Ix=168 x 10 mm²; Iy = 4.58 x 106 mm² y C380X74 flange -BP305x20 -C310X30.8 web X 105.2500- tw- tf # bf P
A built-up section is composed of two (2) channels and a baseplate. To determine its strength against loads, the following should be calculated (note: moment of inertia should be about centroidal x and y axes): [8] Tx (ANSWER: 360.354x10^6 mm^4) [9] Ty (ANSWER: 109.106x10^6 mm^4)| [10] rx (ANSWER: 135.940 mm) Properties of channel (C310x30.8): = A = 3920 mm²; d=305 mm; by 74.7 mm; tw = 7.16mm; t = 12.7 mm; x = 17.7 mm ; 1x = 53.7 x 10 mm²; Iy = 1.61 x 106 mm² Properties of channel (C380x74): A = 9480 mm²; d= 381 mm; b = 94.5 mm ; tw = 18.2 mm; t = 16.5 mm; x = 20.3 mm; Ix=168 x 106 mm²; ly = 4.58 x 106 mm² y flange BP305x20 C310X30.8 web 105.2500- -C380X74 tw- tf bf
Problem 7: Non-circular cross section shaft related to torque problems are difficult to be solved using the basic theory as for circular shaft. Your role is to make use of FAE to analyze the stress in squared cross section shaft shown in Figure.5. g= 6.5(10%) N/cm? e = 0.035 deg 0.5 cm 0.5 cm 0.5 cm- 0.5 cm Figure.5: Squared cross section shaft applied to torque T as 3D model Provide justified explanation and recommendations to simplify the problem from three-dimensional (3D) to two- dimensional (2D). b. а. If the governing boundary value problem equation of such a problem can be given by: + 2g0 = 0, dy? $(x,y) at boundary is 0 dx2
A bracket is riveted to a column by 6 rivets of equal size as shown in Fig. It carries a load of 100 kN at a distance of 250 mm from the column. If the maximum shear stress in the rivet is limited to 63 MPa, find the diameter of the rivet.
Q5
3) A point mass is attached to one end of a beam levered against a spike which acts as the pivot. The point mass weighs 250N and the beam has a uniform mass of 10kg and is 8m long. Parts a and b Part c Fapplied 3 of 6mov 1m 8m Krist 0 = 60° Scale 250 N Scale a. If a scale placed beneath the point mass reads 250N, what is the magnitude and direction for the force at the pivot point? Direction: North, 90° from x-axis Magnitude to k* 250N = 2500 N b. For the same scenario, how far must the pivot point be located relative to the left edge of the beam? (Hint, both the boxes weight and the force from the scale act at the farthest right edge of the beam.) www.acta 0672nos onl c. The pivot is then moved to be 6m from the left edge of the beam which now makes a 60 angle with the floor. How much downward force would be needed at the left-most edge of the beam to reduce the reading on the scale to zero? (Hint: the beam is still in static eq. when the scale reads zero.)
Please Provide correct solution, correct Method. No Missing steps / calculations. No Handwriting please
R10 O Reaction Points 84 cm Loading Points Area = 1594 cm^2 W/2 W/2 54 cm L1=27 cm Figure 2. Skateboard dimensions and loading conditions. Loading conditions Weight of a skateboarder, W 90 kg Load case: Calculate Bending and twisting moment, Ms, Mxy Use Tsai-Wu failure criterion for selection of relevant laminate design. Specifically, the core materials failure is free of any failure; therefore, it can be analyzed based on maximum strain failure criterion with =0.1. D3D20 cm
Course: Statics For Mechanical Engineers C = 655 d = 305 e = 505 f = 1505
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PIOblem soMng Activity sheet (2).docx Microsoft Word (Product Activation Failed) References Mailings Review View 12 A A Aa =,=,|词|MT4| AaBbCcDc AaBbCcDc AaBbC AaBbCc ex, x' 1 Normal 1 No Spaci.. Heading 1 Heading 2 Font Paragraph Styles Chapter 1: Practice problems 1. An axial pull of 40000 N is acting on a bar consisting of three sections of length 30 cm,25 cm and 20 cm and of diameters 2 cm, 4 cm and 5 cm respectively as shown in figure 1. If the Young's modulus = 2 x 105 N/mm2, Calculate: (i) stress in each section and (ii) total extension of the bar. SECTION 3 SECTION 2 SECTION 1 2 cm Oia 4 cm Dia 5 cm Dla 40000 N 40000 N 30 cm 25 cm 20 cm figure 1. 2. A rod 200 cm long and off diameter 3.0 cm is subjected to an axial pull of 30 kN. If the Young's modulus of the material of the rod is 2 x 10° N/mm2, Calculate :(i) stress (ii) strain and (iii) the elongation of the rod. 3. Calculate the Young's modulus of a rod of diameter 30 mm and of length 300 mm which is subjected to a tensile…
Consider the beam shown in (Eigure 1). Suppose that w=360 N/m Figure Ⓒ1of1> 1 of 1 -3m Express your answer to three significant figures and include the appropriate units ▸ View Available Hint(s) F = 675 N Previous Answers ✓ Correct Correct answer is shown. Your answer 674 N was either rounded differently or used a different number of significant figures than required for this part Here we learn how to find a reaction force on a beam at a rocker on an inclined surface caused by an external distributed loading, using equations of equilibrium Part B Determine the and y components of reaction at I using scalar notation Express your answers in newtons to three significant figures separated by a comma. ▸ View Available Hint(s) VAX vec B..B,- 405,540 Submit Previous Answers Incorrect; Try Again; 3 attempts remaining N

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