Differential equation for a simple wheelchair with a suspension system (bumper) can be written as: ?2???2+??????+????=1???. Fe is the gravitational force exerted by the sitting person, 800 N; “m” is mass of the wheelchair, 25 kg; “Ks” is the stiffness (inverse of compliance) of the spring, 2500 N/m; the damping coefficient of the dashpot “B” is 500N/(m/s). How much is the damping coefficient ?of the system? The original of the problem is attached.

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7.Differential equation for a simple wheelchair with a suspension system (bumper) can be written as: ?2???2+??????+????=1???. Fe is the gravitational force exerted by the sitting person, 800 N; “m” is mass of the wheelchair, 25 kg; “Ks” is the stiffness (inverse of compliance) of the spring, 2500 N/m; the damping coefficient of the dashpot “B” is 500N/(m/s). How much is the damping coefficient ?of the system?

The original of the problem is attached.
7. Differential equation for a simple wheelchair with a suspension system (bumper) can be written as:
d?x
+
m dt
B dx 1 Ks
x =F.. Fe is the gravitational force exerted by the sitting person, 800 N; “m" is
dt2
m
mass of the wheelchair, 25 kg; “Ks" is the stiffness (inverse of compliance) of the spring, 2500 N/m;
the damping coefficient of the dashpot "B" is 500 N/(m/s). How much is the damping coefficient 3
of the system?
Transcribed Image Text:7. Differential equation for a simple wheelchair with a suspension system (bumper) can be written as: d?x + m dt B dx 1 Ks x =F.. Fe is the gravitational force exerted by the sitting person, 800 N; “m" is dt2 m mass of the wheelchair, 25 kg; “Ks" is the stiffness (inverse of compliance) of the spring, 2500 N/m; the damping coefficient of the dashpot "B" is 500 N/(m/s). How much is the damping coefficient 3 of the system?
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