(b)Figure Q5(b) shows three-inertias load for a rotational mechanical system. J isconnected to the wall by a spring with spring constant Kq. Inertia J, and J2 are separatedby a viscous friction with coefficient D,. Inertia J, and Ja are separated by a spring withspring constant K2. Whereas Ja is attached to the wall by a viscous damper withcoefficient D2. The external torque T(t) is exerted to Ja as an input to the system.Formulate the state space equation for this rotational mechanical system by choosingany state as an output.D1N-m-s/radKa-1 N-m/rad1 N-m/rad1N-m-s/radJi=Ja=Ja=1 kg-m1 kg-m 0-1 kg-mFigure Q5(b)

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Formulate the state space equation for this rotational mechanical system by choosing any state as an output.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Concept explainers

Type of Magnetic Material

Every material has a unique composition that defines its magnetic behavior. Some materials get attracted towards a magnet and are called magnetic materials. Based on the magnetic properties held by each material, they are classified into different types.

Question

(b)
Figure Q5(b) shows three-inertias load for a rotational mechanical system. J is
connected to the wall by a spring with spring constant Kq. Inertia J, and J2 are separated
by a viscous friction with coefficient D,. Inertia J, and Ja are separated by a spring with
spring constant K2. Whereas Ja is attached to the wall by a viscous damper with
coefficient D2. The external torque T(t) is exerted to Ja as an input to the system.
Formulate the state space equation for this rotational mechanical system by choosing
any state as an output.
D
1N-m-s/rad
Ka-
1 N-m/rad
1 N-m/rad
1N-m-s/rad
Ji=
Ja=
Ja=
1 kg-m
1 kg-m 0-
1 kg-m
Figure Q5(b)

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