Compound A has molecular formula C5H10. Hydroboration-oxidation of compound A produces a pair of enantiomers, compounds B and C. When treated with HBr, compound A is converted into compound D, which is a tertiary alkyl bromide. When treated with 03 followed by DMS, compound A is converted into compounds E and F. Compound E has three carbon atoms, while compound F has only two carbon atoms. Identify the structures of compounds A, B, C, D, E, and F. 08.38A Draw compound A:
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- An optically active monoterpene (compound A) with molecular formula C10H18O undergoes catalytic hydrogenation to form an optically inactive compound with molecular formula C10H20O (compound B). When compound B is heated with acid, followed by reaction with O3 and then with dimethyl sulfide, one of the products obtained is 4-methylcyclohexanone. Give possible structures for compounds A and B.Compound A has the formula C₂H₁9Cl. B is a C₂H19Br compound. A and B undergo base-promoted E2 elimination to give the same alkene C as the major product as well as different minor products. C reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2,6-dimethylheptane. Addition of HCI to C yields A as the major product. Propose structures for A and B. • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. ● ▾ *%-85 ChemDoodle Qt Jn [F 116Compound A has the formula C9H19Cl. B is a C9H19Br compound.A and B undergo base-promoted E2 elimination to give the same alkene C as the major product as well as different minor products.C reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2,6-dimethylheptane.Addition of HCl to C yields A as the major product.Propose structures for A and B.
- Compound W has molecular formula C₁4H18 and reacts with H₂ to form X. Oxidative cleavage of W with O3 followed by CH3 SCH3 affords Y. What is the structure of W?Compound A of molecular formula C8H14 is reduced by sodium in liquid ammonia to give compound B of molecular formula C8H16. product (Y).Both A and B undergo hydrogenation in the presence of a platinum catalyst to give 2,5-dimethylhexane. Ozonolysis of B with an oxidative workup produces a carboxylic acid of molecular formula C4H8O2. Reaction of B with a peroxyacid gives a chiral C8H14O product, but reaction with bromine gives an achiral C8H14Br2 product. What are the identities of A and B?Compound A of molecular formula C8H₁4 is reduced by sodium in liquid ammonia to give compound of molecular formula C8H16. product (Y). Both A and B undergo hydrogenation in the presence of a platinum catalyst to give 2,5- dimethylhexane. Ozonolysis of B with an oxidative workup produces a carboxylic acid of molecular formula C4H8O2. Reaction of B with a peroxyacid gives a chiral C8H₁40 product, but reaction with bromine gives an achiral C8H₁4Br2 product. What are the identities of A and B? 14 A is 2,5-dimethyl-3-hexyne; B is cis-2,5-dimethyl-3-hexene A is 2,5-dimethyl-3-hexyne; B is trans-2,5-dimethyl-3-hexene A is 2,5-dimethyl-1,5-hexadiene; B is 2,5-dimethyl-3-hexyne A is 2,5-dimethyl-2,4-hexadiene; B is cis-2,5-dimethyl-3-hexene
- Compound X has molecular formula C5H10. In the presence of a metal catalyst, compound X reacts with one equivalent of molecular hydrogen to yield 2-methylbutane. (1) Suggest three possible structures for compound X. (2) Hydroboration-oxidation of compound X yields a product with no chirality centers. Identify the structure of compound X.Compound AA has a molecular formula of C3H6O and gives a positiveresult using Tollen’s reagent. The reaction of compound AA with hotacidified potassium permanganate, KMnO4 gives compound BB. Thecatalytic hydrogenation of compound AA with nickel, Ni producedcompound CC. The reaction of compound BB with ethanamine,CH3CH2NH2 produces compound DD I) Draw the structural formula of compounds AA, BB, CC and DD. 2)Name the type of chemical reaction for the formation of compound CC.Compound J, C16H16Br2, is optically active. On treatment with strong base, compounds K and L (each C16H14) are formed; K and L each absorb only 2 equivalents of hydrogen when reduced over a Pd/C catalyst. Compound K reacts with ozone to give phenylacetic acid (C6H5CH2COOH), while similar treatment of L gives 2 products. One product, M, is an aldehyde with formula C7H6O; the other product is glyoxal (CHO)2. Draw the structure of compound L.
- Compound A (C11H23Br) is a secondary alkyl halide. On being heated with a solution of sodium ethoxide in ethanol, compound A yielded a mixture of two alkenes B and C, each having molecular formula C11H22. Catalytic hydrogenation of the major isomer B or the minor isomer C gave only 3,5-diethylheptane. Draw structures for compounds A, B, and C consistent with these observations.A, a compound with molecular formula C6H10, contains three methylene units. A reacts with one equivalent of H2 over Pd/C to yield B. A reacts with aqueous acid to form a single product, C, and undergoes hydroboration/oxidation to form a pair of enantiomers, D and E. Ozonolysis of A followed by reaction with dimethyl sulfide forms F with molecular formula C6H10O2. Provide structures for A–F.Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2 SO4 gives E (C10 H16), which decolorizes two equivalents of Br2 to give F (C10H16 Br4). E undergoes hydrogenation with excess H2 and a Pt catalyst to give isobutylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.