pH 2 4 12 10 8 Titration Data Titration Curve of a Diprotic Organic Acid 1st Equivalence Point (12.0 mL) 2nd Equivalence Point (24.8 mL) 1st Halfway Point (6.0 mL, pH = 2.63) 2nd Halfway Point (18.4 mL, pH = 9.2) pKa29.2 Ka₂ = 6.31 x 10-10 pka 63 2.39 × 10-3 0 5 10 15 20 20 Volume of NaOH (mL) 25 9.2 pH 2.63 pH 1st equivalence point 12ml 1st halfway point 6 ml 2nd halfway point 18.2 ml 2nd equivalence point 24.8
pH 2 4 12 10 8 Titration Data Titration Curve of a Diprotic Organic Acid 1st Equivalence Point (12.0 mL) 2nd Equivalence Point (24.8 mL) 1st Halfway Point (6.0 mL, pH = 2.63) 2nd Halfway Point (18.4 mL, pH = 9.2) pKa29.2 Ka₂ = 6.31 x 10-10 pka 63 2.39 × 10-3 0 5 10 15 20 20 Volume of NaOH (mL) 25 9.2 pH 2.63 pH 1st equivalence point 12ml 1st halfway point 6 ml 2nd halfway point 18.2 ml 2nd equivalence point 24.8
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Chapter7: Sollutions And Colloids
Section: Chapter Questions
Problem 7.7E: Define the term miscible. It is not defined in the text.
Related questions
Question
1. Compare your pKa, Ka and molar mass from your experiment to the expected values for KHP. How well do they compare? What might account for the differences?
2. Based on your results in Part 1, is the method used reliable in determining pKa, Ka and molar mass of a weak acid? Explain.
3. Discuss your thinking on how you determined the identity of your unknown. Were there two (or more) acids that were difficult for you to distinguish between? If so, how did you makeyour final decision?
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