Calculate protein concentration in unknown samples 1, 2, 3: Absorbance of Unknown 1 = 0.541 Absorbance of Unknown 2 = 0.85 Absorbance of Unknown 3 = 1.02 Standard Curve: Y = 0.0073x
Calculate protein concentration in unknown samples 1, 2, 3: Absorbance of Unknown 1 = 0.541 Absorbance of Unknown 2 = 0.85 Absorbance of Unknown 3 = 1.02 Standard Curve: Y = 0.0073x
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Question
Calculate protein concentration in unknown samples 1, 2, 3:
Absorbance of Unknown 1 = 0.541
Absorbance of Unknown 2 = 0.85
Absorbance of Unknown 3 = 1.02
Standard Curve: Y = 0.0073x
![The table displayed is used to record data from an experiment involving bovine serum albumin (BSA) at a concentration of 1.0 mg/ml. The variables in the table are as follows:
1. **BSA Volume (µl):** Quantities of BSA solution used, ranging from 0.0 to 50.0 µl.
2. **[BSA] (µg/ml):** Calculated concentration of BSA, with values from 10 to 50 µg/ml.
3. **Absorbance at 595 nm:** Measured absorbance values, showing how much light is absorbed at a wavelength of 595 nm. The values range from 0.371 to 1.253.
4. **Net Absorbance at 595 nm:** Calculated by subtracting the blank absorbance from the sample absorbance. The data shows values between 0.188 and 0.882.
Below the table, a calculation is shown for converting BSA volume into concentration:
- Formula: \( x = \frac{1 \text{mg} \times 10 \mu\text{l}}{1 \text{ml}} \)
- Result: \( x = 10 \mu\text{g}/\mu\text{l} \)
There is also a note indicating that the "Net Absorbance" is calculated as "sample - blank." An example calculation given is:
- \( (0.707 - 0.371) \), leading to a net absorbance of 0.336.
This data is commonly used to create calibration curves for estimating the concentration of proteins in samples using spectrophotometric analysis.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F790f8b68-f3fd-4a91-a49b-9e15d31eab3c%2F708364f9-fff0-40bf-a692-4a15f6e2c7fd%2Flnyydr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The table displayed is used to record data from an experiment involving bovine serum albumin (BSA) at a concentration of 1.0 mg/ml. The variables in the table are as follows:
1. **BSA Volume (µl):** Quantities of BSA solution used, ranging from 0.0 to 50.0 µl.
2. **[BSA] (µg/ml):** Calculated concentration of BSA, with values from 10 to 50 µg/ml.
3. **Absorbance at 595 nm:** Measured absorbance values, showing how much light is absorbed at a wavelength of 595 nm. The values range from 0.371 to 1.253.
4. **Net Absorbance at 595 nm:** Calculated by subtracting the blank absorbance from the sample absorbance. The data shows values between 0.188 and 0.882.
Below the table, a calculation is shown for converting BSA volume into concentration:
- Formula: \( x = \frac{1 \text{mg} \times 10 \mu\text{l}}{1 \text{ml}} \)
- Result: \( x = 10 \mu\text{g}/\mu\text{l} \)
There is also a note indicating that the "Net Absorbance" is calculated as "sample - blank." An example calculation given is:
- \( (0.707 - 0.371) \), leading to a net absorbance of 0.336.
This data is commonly used to create calibration curves for estimating the concentration of proteins in samples using spectrophotometric analysis.
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