Balancing Equations MatSO202SO3Coefficient Reactant Coefficient Reactant Coefficient Product+Coefficient ProductTally TableLeft TallyColorAtomic SymbolRight Tally

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Chemistry: Matter and Change

1st Edition

ISBN:9780078746376

Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom

Chapter9: Chemical Reactions

Section: Chapter Questions

Problem 59A

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Similar questions

Explain how an equation can be balanced even if the number of reactant particles differs from the number of product particles.
Classify each of the following statements as true or false: a Coefficients in a chemical equation express the molar proportions among both reactants and products. b A stoichiometry problem can be solved with an unbalanced equation. c In solving a stoichiometry problem, the change from quantity of given substance to quantity of wanted substance is based on masses. d Percentage yield is actual yield expressed as a percentage of ideal yield. e The quantity of product of any reaction can be calculated only through the moles of the limiting reactant. f rH is positive for an endothermic reaction and negative for an exothermic reaction.
4.37 The theoretical yield and the actual yield for various reactions are given below. Determine the corresponding percentage yields. Theoretical Yield Actual Yield Reaction 1 35.0 g 12.8 g Reaction 2 9.3 g 120 mg Reaction 3 3.7 metric tons 1250 kg Reaction 4 40.0 g 41.0 g
Carbon dioxide from the atmosphere weathers, or dissolves, limestone (CaCO3) by the reaction CaCO3(s)+CO2(g)+H2O(l)Ca2(aq)+2HCO3(aq) Obtain H for this reaction. See Table 6.2 for the data.
Rewrite the following word equation using chemical formulas. Balance the equation and write the balanced equation in net ionic form: bariumchloride(aq)+sodiumsulfate(aq)sodiumchloride(aq)+bariumsulfate(s)
Collected Volume sodium carbonate (mL) Molarity sodium carbonate (M) Volume calcium chloride (ml) Molarity calcium chloride (M) It changed colors. Observations Mass filter paper (g) Mass filter paper + precipitate (g) Calculated Observed mass calcium carbonate (g) Identify limiting reactant Expected mass calcium carbonate (g) Percent yield (%) 97.0 0.20 100.0 0.20 0.28 2.11 Sodium carbonate
match the following terms with a definition or explanation (there is 6 on the right side the sixth and 5th are pushed together at the bottom)
The theoretical yield and the actual yield for various reactions are given below. Determine the corresponding percentage yields. Reaction 1 Reaction 2 Reaction 3 Reaction 4 Theoretical yield 33.8 g 9.6 g 4.0 metric tons 50.0 g Actual yield 18.8 g 150 mg 1110 kg 51.0 g Percentage yield % % % %
In the reaction of 10.00 mL of FeCl3(aq) and 12.4 g of K2C204(ag), you calculate that 9.58 g of K3FEC2043H2O(s) will be produced. What does 9.58 g represent? percent yield limiting reactant actual yield molar mass theoretical yield
Collected 99.0 Volume sodium carbonate (mL) 0.20 Molarity sodium carbonate (M) Volume calcium chloride (mL) 100.0 Molarity calcium chloride (M) 0.10 Observations foam on top gray Mass filter paper (g) 0.28 Mass filter paper + precipitate (g) 121.1 Calculated Observed mass calcium carbonate (g) Identify limiting reactant Expected mass calcium carbonate (g) Percent yield (%)
MormResponse In order to to determine the limiting reactant in a particular reaction, one must know each of the following EXCEPT the mass of each product formed the mass of each reactant present the molar mass of each reactant present the coefficient of each reactant in a balanced equation
Mass of weighing paper (g) 0.3907 Mass of weighing paper plus aluminum (g) 1.4064 Mass of watch glass (g) 41.4028 Mass of watch glass plus dry alum (g) 54.3336 Mass of aluminum (g) Mass of dry alum (g) Theoretical yield (g) Percent yield (%)

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Balancing Equations Mat SO2 02 SO3 Coefficient Reactant Coefficient Reactant Coefficient Product + Coefficient Product Tally Table Left Tally Color Atomic Symbol Right Tally