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- pls provide clear solution.les/23530384?wrap%3D1 Hwk 17 MOLE.docx OLE.docx 17 MOLE.docx (13.3 KB) ZC Hwk 17 MOLE/ MOLE STOICHIOMETRY 1) First balance the equation The combustion of a sample of butane, C,H10 (lighter fluid), produced 5.75 mol of water. C,H10 + O2 -------> CO,+ H,O a) How many moles of butane burned? b) How much oxygen was used up in moles?4-During the water of crystallization Mass of an empty crucible 40.60 g. experiment, the following data were collected for the hydrated salt use them to solve Q4 and Q5 42.02 g Mass of crucible + hydrated salt Mass of crucible + anhydrous salt 41.35 Molar mass of anhydrous salt 146.5g/mol 4- The % by mass of the water in the salt equals: B. 78.1 % C. 47.2 % D. 52.8% A.21.9 %
- I don't know how to solve everything.9. How many moles of 2 Na(s) * 24- 2. Provide an example calculation for row 8. This requires you to go from g CO2 to g NaHCO3 using stoichiometry. Use equation 2, a net ionic equation for the reaction of acid, H3O* (from acetic acid, CH3COOOH in vinegar) with the bicarbonate (from NaHCO3 in pill) to determine the molar ratio for your calculation. Note that Na+ (aq) doesn't show up in this equation because it is a spectator ion. Hag) HUse 1 decimal point for all atomic masses. 2.00 g of H2(g) are reacted with 32.0 g of O2(g) by the following reaction 2H2(g) + O2(g) --> 2H2O(g) What is the limiting reagent? H2(g) O2(g) Based on the limiting reagent, fill in the following ICE Table using moles. Enter any zero values as 0.00. H2 O2 H2O Initial Change Final How much of the excess reagent remains (in grams)?
- 9Mass of Na2CO3.H2O (g) = 2.12g (g) Mass of the CaCl2.2H2O (g) = 1.98g Mass of the top funnel + filter paper (g) = 15.85g Mass of top funnel + filter paper + CaCO3 collected (g) = 17.81g CaCl2 + Na2CO3 ==== CaCo3 + 2NaCl Moles CaCO3 produced by Na2CO3 (if all Na2CO3 reacts)? Moles CaCO3 produced by Na2CO3 (if all CaCl2 reacts)? What is the Limiting Reagent? Moles Na2CO3 reacting? Moles CaCl2 reacting?Use 1 decimal point for all atomic masses. 12.1 g of C2H4(g) are reacted with 0.924 g of HCl(g) by the following reaction: C2H4(g) + HCl(g) --> C2H5Cl(g) What is the limiting reagent? HCl(g) C2H4(g) Based on the limiting reagent, what should the yield of C2H5Cl(g) be?
- Given the reaction: + HF a. Balance the reaction. 24 b. A student mixes 3.0 g N₂H with 6.33 x 10 molecules of F, gas. Determine i. The limiting reactant ii. The mass of HF gas produced if the reaction is 83.0 % efficient. NH + ____F₂- F, → ___________N₂ 2Answer d,e,fSamples of hydrated manganese perchlorate are heated to determine the amount of crystal water: Mn(CIO4)2 nH20 -» Mn(CIO4)2 nH20 A sample of 2.126 g weighs 1.473g after heating. The mass of water that evaporated is: The molar ratio of water to manganese perchlorate up to two decimal points is: a.u