Assuming that variables i and j are stored in registers $s0 and $s1 and integer array A is located at the address stored in register $s2, translate the following code snippets to MIPS assembly language: 1. if(i == j) A[0] = i; else 2. A[0] =j; for(i=0; i

Assuming that variables i and j are stored in registers $s0 and $s1 and integer array A is located at the address stored in register $s2, translate the following code snippets to MIPS assembly language: 1. if(i == j) A[0] = i; else 2. A[0] =j; for(i=0; i

Name: Assuming that variables i and j are stored in registers $50 and $s1an
Uploaded: 2024-03-20T06:51:23.000Z
Channel: Bartleby
Description: Assuming that variables i and j are stored in registers $50 and $s1and integer array A is located at the address stored in register $s2,translate the following code snippets to MIPS assembly language:1.if(i == j)A[0] = i;elseA[0] =j;2.for(i = 0; i

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Take the following program and translate it into PEP/9 assembly language: #include <iostream> using namespace std; int fib(int n) { int temp; if (n <= 0) return 0; else if (n <= 2) return 1; else { temp = fib(n – 1); return temp + fib(n-2); } } int main() { int num; cout << "Which fibonacci number? "; cin >> num; cout << fib(num) << endl; return 0; } You must use equates to access the stack and follow the call to the function as discussed in the book (pass the parameter, return address, return a value and so on). There are NO global variables in the resulting code (except a global message of "Range num? "). It must be able to do sum a range greater than 2. comments would be appreciated
**ARM language**Assuming that L, N, LEnd and p are held in registers R1, R2, R3 and R4 respectively, give the ARMassembly language code which corresponds to the two statements p+= *L; L++; in Plus2int Plus2( int *L, int N ) {int *LEnd, p;p = 0;LEnd = L+N;while( L < LEnd ) {p += *L; L++;}return p;}
trtjhrtjhrthrt
PEP/9 Translate the following C++ program into assembly language: #include <iostream> using namespace std; int main() { char letter; int countA = 0, countB = 0, countC = 0; cin >> letter; do { switch (letter) { case 'A' : countA++; break; case 'B' : countB++; break; case 'C' : countC++; break; } cin >> letter; } while (letter != 'X'); cout << "Number of A's " << countA << endl << "Number of B's " << countB << endl << "Number of C's " << countC << endl; return 0; } Use local variables (except for messages, of course) and the branch indexed for the switch statement.
int X[900]; int Y[600]; int sum, sum1, sum2, sum3; //parallelism : dividing outer loop in three parts //i = 1 to 300 for(i=1;i<=300;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } //i = 301 to 600 for(i=301;i<=600;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } //i = 601 to 900 for(i=601;i<=900;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } sum = sum1 + sum2 + sum3;} another way to solve the question that send in the pic
Modify below program to include response timeProgram:ROUND ROBIN CPU SCHEDULING ALGORITHM: #include<stdio.h>#include<conio.h>using namespace std; int main(){int i,j,n,bu[10],wa[10],tat[10],t,ct[10],max; float awt=0,att=0,temp=0;printf("Enter the no of processes--"); scanf("%d",&n);for(i=0;i<n;i++){printf("\nEnter Burst Time for process %d--", i+1); scanf("%d",&bu[i]);ct[i]=bu[i];}printf("\nEnter the size of time slice--"); scanf("%d",&t);max=bu[0];for(i=1;i<n;i++)if(max<bu[i])max=bu[i];for(j=0;j<(max/t)+1;j++)for(i=0;i<n;i++)if(bu[i]!=0)if(bu[i]<=t){tat[i]=temp+bu[i];temp=temp+bu[i];bu[i]=0;}else{bu[i]=bu[i]-t;temp=temp+t;}for(i=0;i<n;i++){wa[i]=tat[i]-ct[i];att+=tat[i];awt+=wa[i];}printf("\nThe Average Turnaround time is--%f",att/n);printf("\nThe Average Waiting time is--%f ",awt/n);printf("\n\tPROCESS\t BURST TIME \t WAITING TIME\tTURNAROUND TIME\n");for(i=0;i<n;i++)printf("\t%d \t %d \t\t %d \t\t %d…
Debug my C code and translate the small code into assembly language. Thank you! #include <stdio.h> #include <stdlib.h> int Length = 4; int Seq[] = {17, 34, 51, 68}; int main() { int Next = 0; //Sets value for Next. int i = 1; // sets initial value for i. while (i != 4){ //condition for while loop. Next = Next + 17; //adds integer value to Next. i++; //post increment for @param i. return Next; //returns value for Next. } // your program should use this print statement printf("The next integer in the sequence: %d\n", Next); return 0; }
Computer Science #include<cmath>#include<stdio.h>__global__voidprocess_kernel1(float *input1,float *input2,float *output,int datasize){int idx = threadIdx.x + blockIdx.x * blockDim.x;int idy = threadIdx.y + blockIdx.y * blockDim.y;int idz = threadIdx.z + blockIdx.z * blockDim.z;int index = idz * (gridDim.x * blockDim.x) * (gridDim.y*blockDim.y) + idy * (gridDim.x * blockDim.x) +idx;if(index<datasize)output[index] = sinf(input1[index]) + cosf(input2[index]);}__global__voidprocess_kernel2(float *input,float *output,int datasize){int idx = threadIdx.x + blockIdx.x * blockDim.x;int idy = threadIdx.y + blockIdx.y * blockDim.y;int idz = threadIdx.z + blockIdx.z * blockDim.z;int index = idz * (gridDim.x * blockDim.x) * (gridDim.y*blockDim.y) + idy * (gridDim.x * blockDim.x) +idx;if(index<datasize)output[index] = logf(input[index]);}_global__voidprocess_kernel3(float *input,float *output,int datasize){int idx = threadIdx.x + blockIdx.x *…
Computer organisation ! Use RARS simulator to write and execute the two codes below using RISC-V Assembly language.
Write the MIPS assembly language equivalent of the following code. int[] numbers = {1,1,0,0,0,0,0,0,0,0,0,0,0,0};int i = 0;while (i < 12){numbers[i+2] = numbers[i+1] + numbers[i];i++;}for (int j = 0; j < 14; j++){System.out.println(numbers[j]);}
Assembly language
// Example 8.27b void Func(int a[], int & r) { int i; int induction = r; for (i = 0; i < 100; i += 2) { a[i] = induction; a[i+1] = induction; induction++; }}Write the assembly code generated by the assembler from example 8.27b.