int i;float x[5], y[5];[ lots of code deleted... ]for (i=0;i<5;i++)if (x[i] > y[i])x[i] = x[i] + y[i];[ more code deleted... ]Translate to MIPS assembly language:

Note: This question asked for the conversion of the given code into MIPS assembly language only. So,…

Answered: { int i; float x[5], y[5]; [ lots of…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

See similar textbooks

Similar questions

Help me with this
Consider the following C code: 1: int main() { 2: 3: 4: 5: } int y = 5; // Return y times 4 return y* 4; What is removed during the preprocessing step of compilation? A. Line 1 B. Line 3 C. Line 5 D. Lines 3 and 5 E. Everything, since it will be assembly after the preprocessing step
NAND2TETRIS HARDWARE SIMULATOR HiLoMux - This has one 8-bit input bus, in, and one 4-bit output bus, out. Alsopresent is a sel input, which is used to select what appears on out. Ifsel is false, then out should contain the lower 4-bits of in (i.e. in[0],in[1], in[2], in[3]). If sel is true, then out should contain theupper 4-bits of in (i.e. in[4] mapped to out[0], in[5], mapped toout[1], etc.). In other words, the HiLoMux can be used to select anibble from a byte please use the skeleton program below CHIP HiLoMux{ IN in[8], sel; OUT out[4]; PARTS: }
Translate C program to Pep/9 assembly language. /C code for 6.19a#include <stdio.h>char myChar;char toLower(char ch) { if ((ch >= ’A’) && (ch <= ’Z’)) { return ch + ’a’ - ’A’; } else { return ch; }}int main () { scanf(”%c”, &myChar); printf(”%c\n”, toLower(myChar)); return 0;}
Please your code should be in mips assembly language
convert this code to java language /* OPERATING SYSTEMS LAB PROJECT* AKASH JAIN* 179303013* DESIGNING A VIRTUAL MEMORY MANAGER*/ #include<stdio.h>#include<stdlib.h>#include<string.h> const int VM_SIZE=256;const int PAGE_SIZE=256;const int TLB_SIZE=16;const int MM_SIZE=256; int main(int argc, char* argv[]){FILE *fd;if(argc<2){printf("NOT ENOUGH AGRUMENTS\n EXITING\n");return 0;}fd=fopen(argv[1],"r");if(fd==NULL){printf("ERROR OPENING FILE\n FILE FAILED TO OPEN\n");return 0;}char *value=NULL;size_t len=0;ssize_t read;long long page_no,offset,page_table,totalhits=0,fault=0,pages=0;int qp=0; //to maintain the queue positionint physicalad=0,frame,logicalad;int tlb[TLB_SIZE][2];int pagetable[PAGE_SIZE]; memset(tlb,-1,TLB_SIZE*2*sizeof(tlb[0][0]));memset(pagetable,-1,sizeof(pagetable));int mask=255,mask1=62580,i,hit;while((read=getline(&value,&len,fd))!=-1){pages++;//get page number and offset from logical…
Take the following program and translate it into PEP/9 assembly language: #include <iostream> using namespace std; int fib(int n) { int temp; if (n <= 0)    return 0; else if (n <= 2)    return 1; else {    temp = fib(n – 1);    return temp + fib(n-2); } } int main() {    int num;    cout << "Which fibonacci number? ";    cin >> num;    cout << fib(num) << endl;    return 0; } You must use equates to access the stack and follow the call to the function as discussed in the book (pass the parameter, return address, return a value and so on). There are NO global variables in the resulting code (except a global message of "Range num? "). It must be able to do sum a range greater than 2. comments would be appreciated
Convert the following into Pep/9 Assembler: #include using namespace std; int square(int n){     int i;     int sq;     sq = 0;     for (i = 0; i < n; i++){         sq = sq + n;     }     return sq; } int main (){     int num; cout << "Enter a number: ";     cin >> num;     cout << num << " squared = "          << square(num)          << endl;     return 0; }
Convert the following into Pep/9 Assembler: #include <iostream>using namespace std;int square(int n){    int i;    int sq;    sq = 0;    for (i = 0; i < n; i++){        sq = sq + n;     }    return sq;}int main (){    int num; cout << "Enter a number: ";     cin >> num;    cout << num << " squared = "          << square(num)          << endl;    return 0;} Submit: Source file along with screen captures showing the program running in the Pep simulator.
Take the following program and translate it into PEP/9 assembly language: #include <iostream> using namespace std; int theArray[] = { 5, 11, -29, 45, 9, -1}; void sumPos(int ary[], int len, int &sum) { sum = 0; for (int i = 0; i < len; i++) if (ary[i] > 0) sum = sum + ary[i]; } int main() { int total; sumPos(theArray, 6, total); for (int k=0; k < 6; k++) cout << theArray[k] << endl; cout << "Positive sum is " << total << endl; return 0; } You must use equates to access the stack and the index register in accessing the array. Remember, the sumPos array does NOT know about the global "theArray" – the address of the array must be passed via the parameter. make theArray a local array in main. Submit source code add comments
s. Convert the following C code to assembly language using vector operations. (Just do your best, make necessary assumptions, don't worry about syntax too much.) for (i-0;i <300; i++) { c_re[i] = a_re[i] b_re[i]-a_im[i] * b_im[i]: c_im[i] - a_re[i] b_im[i]+a_im[i] * b_re[i];
Example: The Problem Input File Using C programming language write a program that simulates a variant of the Tiny Machine Architecture. In this implementation memory (RAM) is split into Instruction Memory (IM) and Data Memory (DM). Your code must implement the basic instruction set architecture (ISA) of the Tiny Machine Architecture: //IN 5 //OUT 7 //STORE O //IN 5 //OUT 7 //STORE 1 //LOAD O //SUB 1 55 67 30 55 67 1 LOAD 2- ADD 3> STORE 4> SUB 5> IN 6> OUT 7> END 8> JMP 9> SKIPZ 31 10 41 30 //STORE O 67 //OUT 7 11 /LOAD 1 //OUT 7 //END 67 70 Output Specifications Each piece of the architecture must be accurately represented in your code (Instruction Register, Program Counter, Memory Address Registers, Instruction Memory, Data Memory, Memory Data Registers, and Accumulator). Data Memory will be represented by an integer array. Your Program Counter will begin pointing to the first instruction of the program. Your simulator should provide output according to the input file. Along with…

SEE MORE QUESTIONS

Recommended textbooks for you

Computer Networking: A Top-Down Approach (7th Edi…

Computer Engineering

ISBN:

9780133594140

Author:

James Kurose, Keith Ross

Publisher:

PEARSON

Computer Organization and Design MIPS Edition, Fi…

Computer Engineering

ISBN:

9780124077263

Author:

David A. Patterson, John L. Hennessy

Publisher:

Elsevier Science

Network+ Guide to Networks (MindTap Course List)

Computer Engineering

ISBN:

9781337569330

Author:

Jill West, Tamara Dean, Jean Andrews

Publisher:

Cengage Learning

Computer Networking: A Top-Down Approach (7th Edi…

Computer Engineering

ISBN:

9780133594140

Author:

James Kurose, Keith Ross

Publisher:

PEARSON

Computer Organization and Design MIPS Edition, Fi…

Computer Engineering

ISBN:

9780124077263

Author:

David A. Patterson, John L. Hennessy

Publisher:

Elsevier Science

Network+ Guide to Networks (MindTap Course List)

Computer Engineering

ISBN:

9781337569330

Author:

Jill West, Tamara Dean, Jean Andrews

Publisher:

Cengage Learning

Concepts of Database Management

Computer Engineering

ISBN:

9781337093422

Author:

Joy L. Starks, Philip J. Pratt, Mary Z. Last

Publisher:

Cengage Learning

Prelude to Programming

Computer Engineering

ISBN:

9780133750423

Author:

VENIT, Stewart

Publisher:

Pearson Education

Sc Business Data Communications and Networking, T…

Computer Engineering

ISBN:

9781119368830

Author:

FITZGERALD

Publisher:

WILEY

SEE MORE TEXTBOOKS

{ int i; float x[5], y[5]; [ lots of code deleted... ] for (i=0;i<5;i++) if (x[i] > y[i]) x[i] = x[i] + y[i]; [ more code deleted... ] Translate to MIPS assembly language: