In c++ write an assembler in which it will read a program written in HACK assembly language from an external file and ultimatley translate each line of code into the binary equivalent that can be run on the computer I built so based off the following hdl files Computer below others are in the images.CHIP Computer { IN reset; PARTS: //Read-only memory (ROM) for instruction fetch ROM32K(address=PC,out=instruction); //Central Processing Unit (CPU) for instruction executionCPU(instruction=instruction,reset=reset,inM=outMemo,outM=CPUoutM,writeM=wM,addressM=adM,pc=PC); //Memory for data storage and control logic Memory(in=CPUoutM,load=wM,address=adM,out=outMemo); } CHIP Memory {}IN in [16], load, address [15];OUT Out[16];PARTS://Determines whether to load data into RAM or screen based on//the load signal and address bitDMux (in=load, sel-address [14], a=ramload, b=skload);//Separates the screen load signal from the decision to load screen dataDMux (in=skload, sel-address [13],a=sload, b=nothing);//Loads data into RAM and screen based on the selectionRAM16K (in=in, load=ramload, address address [0..13], out=ramout);Screen (in-in, load=sload, address=address [0..12], out=screenout);//Deals with keyboard, ensures that bits in [0..12] are set to eKeyboard (out-kbd);//Determines keyboard input validity by checking bits in [0..12]Or8way (in=address [0..7], out=notkbd1);Orsway (in [0..4]=address [8..12], in[5..7]=false, out=notkbd2);or (a=notkbd1, b=notkbd2, out=notkbd);//Selects either keyboard input or zero based on the keyboard validityMux16(a=kbd,b=false, sel-notkbd, out=kbdout);//Determine the output based on RAM, screen, and keyboard dataMux16(a=ramout, b-outsk, sel-address [14], out-out);Mux16(a=screenout, b=kbdout, sel=address [13], out-outsk); CHIP CPU {}IN inM[16],instruction [16], // Instruction for executionreset;// M value input (M = contents of RAM[A])OUT OutM[16],writem,addressM[15],pc [15];// Signals whether to re-start the current// program (reset=1) or continue executing// the current program (reset=0).// M value output// write into M?// Address in data memory (of M)// address of next instructionPARTS://Extracts instruction bit for addressing memory (A-in)Mux16(a=instruction, b=ALUout, sel-instruction [15], out=Ain);//Computes the inverse of instruction [15]Not (in=instruction [15], out=notinstruction);//Determines if the instruction implies loading A-register with a constant valueor (a=notinstruction, b=instruction [5], out=loadA); //Controls bit di//Loads A-register based on the instruction and prepare A-value for ALUARegister (in=Ain, load=loadA, out-Aout, out [e..14]=addressM);//Chooses between Aout and inM as ALU input based on the instruction [12] bitMux16(a=Aout, b=inM, sel-instruction [12], out=AMout);//Prepares ALU control bits for various operationsAnd (a=instruction [11], b=instruction [15], out=zx);And (a=instruction [10],b=instruction [15], out=nx);or (a=instruction [9],b=notinstruction, out=zy);or (a=instruction [8],b=notinstruction, out=ny);And (a=instruction [7],b=instruction [15], out=f);And (a=instruction [6],b=instruction [15], out=no);ALU (x=Dout, y=AMout, zx=zx, nx=nx, zy=zy, ny=ny,f=f, no=no, out-out, out=ALUout, zr=zero, ng=neg);//Determines if the instruction allows writing to memoryAnd (a=instruction [15],b=instruction [3], out=writeM); //Controls bit d3//Controls bit cl//Controls bit c2//Controls bit c3//Controls bit c4//Controls bit c5//Controls bit c6//Loads D-register based on the instructionAnd (a=instruction [15],b=instruction [4], out=loadD); //Controls bit d2DRegister (in=ALUout, load=loadD, out=Dout);//Determines the jump condition based on the instruction bitsor (a=zero, b=neg, out=notpos);Not (in=notpos, out=pos);And (a=instruction[e],b=pos, out=j3); //Controls bit j3And (a=instruction [1],b-zero, out=j2);//Controls bit j2And (a=instruction [2],b=neg, out=j1);//Controls bit jior (a=j1, b=j2, out=j12);or (a=j12, b=j3, out=j123);And (a=j123, b=instruction [15], out=jump);//Loads the program counter (PC) based on the jump conditionPC (in-Aout, load-jump, reset=reset, inc=true, out [0..14]=pc);

Assembly languages serve as a bridge between the human-readable mnemonic representation of…

Answered: In c++ write an assembler in which it…

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE