Translate the following C program to Pep/9 assembly language. #include int inpNum, sum, count, min; int main() { sum = 0; count = min = 0; 32767; printf("? "); scanf("%d", &inpNum); while (inpNum != 0 ) { sum += inpNum; count++; if (inpNum < min) { min = inpNum; } printf("? "); scanf("%d", &inpNum); } // end while printf("Sum printf("Count = printf("Min } // end of main = %d\n", sum); = %d\n", count); %d\n", min);

Translate the following C program to Pep/9 assembly language. #include int inpNum, sum, count, min; int main() { sum = 0; count = min = 0; 32767; printf("? "); scanf("%d", &inpNum); while (inpNum != 0 ) { sum += inpNum; count++; if (inpNum < min) { min = inpNum; } printf("? "); scanf("%d", &inpNum); } // end while printf("Sum printf("Count = printf("Min } // end of main = %d\n", sum); = %d\n", count); %d\n", min);

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

See similar textbooks

Related questions

Q: const int limit = 5; int main(){ int number; cin >> number; while (number < limit){…

A: The following is the program : __gthread_key_delete(int): str fp, [sp, #-4]! add…

Q: ranslate the following code into pep9 assembly language and show the screenshot of pep9 code.…

A: This is the lowest level of computing (machine language). It has seven registers and four status…

Q: Translate the following c++ program into pep9 assembly language. #include using namespace std; int…

A: The converted assembly code is

Q: How does the concept of "garbage collection" apply to memory management in programming languages…

A: Memory management is a critical aspect of programming, particularly in languages like Java. In these…

Q: Translate the following c++ code into pep9 assembly language #include using namespace std; int…

A: Converted Code: _ZSt4endlIcSt11char_traitsIcEERSt13basic_ostreamIT_T0_ES6_@plt: jmpq…

Q: #include using namespace std; const numLoops = 10; int main(){ int x = 0; do { cout <<…

A: main: push rbp mov rbp, rsp sub rsp, 16 mov DWORD PTR…

Q: ranslate the variable/constant declarations in the following C++ code snippet into Pep/9 assembly…

A: Pep/9 assembly: BR main LIMIT: .EQUATE 100 ;…

Q: What are some of the parallels that can be seen between a reference and a pointer

A: Answer is given below

Q: ; sq = 0; for (i = 0; i < n; i++){ sq = sq + n; } return sq;

A: To Convert : #include <iostream>using namespace std;int square(int n){ int i; int sq;…

Q: translate a c++ program into pep/9 assembly language #include using namespace std; int myAge;…

A: Steps followed to convert the given program from c++ to pep9: Two variables are declared. myAge is…

Q: Convert the following c++ code into pep9 assembly language. #include using namespace…

A: $ cat find_times.s.file "find_times.C".local _ZStL8__ioinit.comm _ZStL8__ioinit,1,1.text.globl…

Q: Use a stack to order a sequence of floating point numbers in increasing order of their values. The…

A: Here is your solution -

Q: n what ways do these points suffer from poor design? There can typically be only one kind of…

A: This statement suffers from poor design in a few ways:

Q: Please translate the following c program below to a pep/9 assembly language and please Also explain…

A: Pep/9 Assembly code for the given C code is provided in the next step.

Q: int machineCompare1(struct machine* mac1, struct machine* mac2) { struct mac1; struct mac2;…

A: Answer: C Source Code: #include <stdio.h>#include <string.h> struct machine{ char…

Q: Convert the following c++ code into pep9 assembly language #include using namespace std; int…

A: Sample simulator:

Q: Convert the following c++ code into pep9 assembly language. #include using namespace std;…

A: times(int&, int, int): push rbp mov rbp, rsp mov QWORD PTR…

Question

Translate the following C program to Pep/9 assembly language.
#include <stdio.h>
int inpNum, sum, count, min;
int main() {
sum = 0;
count =
0;
min = 32767;
printf("? ");
scanf("%d", &inpNum);
while (inpNum != 0 ) {
sum += inpNum;
count++;
if (inpNum < min) {
min = inpNum;
}
printf("? ");
scanf("%d", &inpNum);
} // end while
printf("Sum
printf("Count
printf("Min
} // end of main
=
=
%d\n", sum);
=
%d\n", count);
%d\n", min);

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Similar questions

How does the concept of 'garbage collection' contribute to memory management in programming languages?
Convert the following c++ code into pep9 assembly language. #include <iostream> using namespace std; void times(int& prod, int mpr, int mcand) { prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } } int main(){ int product, n, m; cout << "Enter two numbers: "; cin >> n >> m; times(product, n, m); cout << "Product: " << product << endl; return 0; }
Convert the following c++ code into pep9 assembly language #include <iostream> using namespace std; void times(int& prod, int mpr, int mcand) { prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } } int main(){ int product, n, m; cout << "Enter two numbers: "; cin >> n >> m; times(product, n, m); cout << "Product: " << product << endl; return 0; }
Convert the following into Pep/9 Assembler: #include using namespace std; int square(int n){     int i;     int sq;     sq = 0;     for (i = 0; i < n; i++){         sq = sq + n;     }     return sq; } int main (){     int num; cout << "Enter a number: ";     cin >> num;     cout << num << " squared = "          << square(num)          << endl;     return 0; }
Convert the following into Pep/9 Assembler: #include <iostream>using namespace std;int square(int n){    int i;    int sq;    sq = 0;    for (i = 0; i < n; i++){        sq = sq + n;     }    return sq;}int main (){    int num; cout << "Enter a number: ";     cin >> num;    cout << num << " squared = "          << square(num)          << endl;    return 0;} Submit: Source file along with screen captures showing the program running in the Pep simulator.
Complete the following C++ programs into Pep/9 assembly language: 1) int main(){int cop;    int driver;    cop = 0;    driver = 40;    while (cop <= driver) {        cop += 25;        driver += 20;    }    cout << cop;    return 0;}
Example: The Problem Input File Using C programming language write a program that simulates a variant of the Tiny Machine Architecture. In this implementation memory (RAM) is split into Instruction Memory (IM) and Data Memory (DM). Your code must implement the basic instruction set architecture (ISA) of the Tiny Machine Architecture: //IN 5 //OUT 7 //STORE O //IN 5 //OUT 7 //STORE 1 //LOAD O //SUB 1 55 67 30 55 67 1 LOAD 2- ADD 3> STORE 4> SUB 5> IN 6> OUT 7> END 8> JMP 9> SKIPZ 31 10 41 30 //STORE O 67 //OUT 7 11 /LOAD 1 //OUT 7 //END 67 70 Output Specifications Each piece of the architecture must be accurately represented in your code (Instruction Register, Program Counter, Memory Address Registers, Instruction Memory, Data Memory, Memory Data Registers, and Accumulator). Data Memory will be represented by an integer array. Your Program Counter will begin pointing to the first instruction of the program. Your simulator should provide output according to the input file. Along with…
translate a c++ program into pep/9 assembly language #include <iostream> using namespace std; int myAge;void ShowVal(int age){ cout << "Age:" << age << endl;} int main() {cout << "Enter age: ";cin >> myAge;ShowVal(myAge);return 0;}
15. Translate the following C program to Pep/9 assembly language. #include int main() { int numitms, j, data, sum; scanf("%d", &numItms); sum = 0; for (j = 1; j <= numitms; j++) { scanf("%d", &data); sum += data; } printf ("Sum: %d\n", sum); return 0; } Sample Input 48-376 Sample Output Sum: 18