Please translate the following c program below to a pep/9 assembly language and please Also explain the code.
Please translate the following c program below to a pep/9 assembly language and please Also explain the code.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Please translate the following c program below to a pep/9 assembly language and please Also explain the code.

Transcribed Image Text:```c
int number, base, answer;
int divide(int numer, int denom) {
int quotient, remain;
remain = numer;
quotient = 0;
while (remain >= denom) {
remain -= denom;
quotient++;
} // end for
return quotient;
} // end of divide()
void findLog(int *result, int num, int b) {
int k;
num--;
*result = 0;
while (num > 0) {
*result = *result + 1;
num = divide(num, b);
} // end while
} // end of findLog()
```
### Explanation
This code snippet contains two functions: `divide` and `findLog`.
1. **divide(int numer, int denom)**
- This function takes two integers, `numer` and `denom`, and performs integer division.
- It calculates how many times `denom` can be subtracted from `numer` before the remainder is less than `denom`.
- The result, `quotient`, is returned.
2. **findLog(int *result, int num, int b)**
- This function calculates the logarithm of `num` to the base `b`.
- The variable `num` is decremented by 1 initially.
- A while loop repeatedly calls the `divide` function to update `num` by dividing it by `b`.
- Each time the loop runs, it increments the value pointed by `result`.
- This continues until `num` is no longer greater than 0.
- The final value of `*result` gives the logarithm result.
The code is a basic implementation of integer division and logarithm using iterative methods in C.
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