What addresses in memory contain array A?
Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
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Machine organization
What addresses in memory contain array A?
![### Translating a Java Program to LC3 Assembly Language
#### Java Program:
This simple Java program initializes an array `A` of size 10 with all elements set to 0.
```java
for (i = 0; i < 10; i++) {
A[i] = 0;
}
```
#### Corresponding LC3 Assembly Code:
The provided assembly code performs the same task as the Java program above, initializing 10 memory locations starting from a specific address with the value 0.
```assembly
.ORIG x3000 ; Set the starting memory address for the program
AND R0, R0, #0 ; Clear R0, i.e., set R0 to 0
AND R5, R5, #0 ; Clear R5, i.e., set R5 to 0
LD R1, ADDRA ; Load the base address of the array into R1
LD R2, MINUS10 ; Load -10 into R2 for the loop comparison
LOOP:
ADD R3, R0, R2 ; R3 = R0 - 10, compare i < 10
BRz DONE ; If i == 10, branch to DONE
ADD R4, R1, R0 ; Compute the address of A[i]
STR R5, R4, #0 ; Store 0 at A[i]
ADD R0, R0, #1 ; Increment i (R0)
BR LOOP ; Repeat the loop
DONE:
HALT ; End of the program
ADDRA .FILL x4000 ; Starting address of the array
MINUS10 .FILL #-10 ; Constant -10
.END ; End of the assembly source file
```
### Detailed Explanation:
1. **Initialization and Clearing Registers:**
- `.ORIG x3000`: The program starts at memory address `x3000`.
- `AND R0, R0, #0`: Sets register `R0` to 0, representing the loop counter `i`.
- `AND R5, R5, #0`: Sets register `R5` to 0, which will be stored in each element of the array.
2. **Loading Constants:**
- `LD R1, ADDRA`: Loads the base address of the array into register `R1`.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe019b336-5feb-4f7e-87ed-8ba822dc1cb1%2F530e22e1-7292-415c-ab65-6bd69ad79bc0%2Fg322ftwh_processed.png&w=3840&q=75)
Transcribed Image Text:### Translating a Java Program to LC3 Assembly Language
#### Java Program:
This simple Java program initializes an array `A` of size 10 with all elements set to 0.
```java
for (i = 0; i < 10; i++) {
A[i] = 0;
}
```
#### Corresponding LC3 Assembly Code:
The provided assembly code performs the same task as the Java program above, initializing 10 memory locations starting from a specific address with the value 0.
```assembly
.ORIG x3000 ; Set the starting memory address for the program
AND R0, R0, #0 ; Clear R0, i.e., set R0 to 0
AND R5, R5, #0 ; Clear R5, i.e., set R5 to 0
LD R1, ADDRA ; Load the base address of the array into R1
LD R2, MINUS10 ; Load -10 into R2 for the loop comparison
LOOP:
ADD R3, R0, R2 ; R3 = R0 - 10, compare i < 10
BRz DONE ; If i == 10, branch to DONE
ADD R4, R1, R0 ; Compute the address of A[i]
STR R5, R4, #0 ; Store 0 at A[i]
ADD R0, R0, #1 ; Increment i (R0)
BR LOOP ; Repeat the loop
DONE:
HALT ; End of the program
ADDRA .FILL x4000 ; Starting address of the array
MINUS10 .FILL #-10 ; Constant -10
.END ; End of the assembly source file
```
### Detailed Explanation:
1. **Initialization and Clearing Registers:**
- `.ORIG x3000`: The program starts at memory address `x3000`.
- `AND R0, R0, #0`: Sets register `R0` to 0, representing the loop counter `i`.
- `AND R5, R5, #0`: Sets register `R5` to 0, which will be stored in each element of the array.
2. **Loading Constants:**
- `LD R1, ADDRA`: Loads the base address of the array into register `R1`.
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