Asimple horizontal curve has: A = 46" 18" L = 215m Station PC = (15+25), Coordinate of P.I = (450, 620) and Azimuth of (P.I P.T) =112° 18' calculate: 1-All elements and station of main Points 2- Coordinates of station (P.C and P.T) OR T ③ C LTRA 188 Д T = R tan A C=2R sin 2 D E=RL-c's + -1) A 2 M=R (1- Cos) sta PC sta PI - T sta P.T= sta P.C+L L DE ⑥M P.I P.C T T R PT
Asimple horizontal curve has: A = 46" 18" L = 215m Station PC = (15+25), Coordinate of P.I = (450, 620) and Azimuth of (P.I P.T) =112° 18' calculate: 1-All elements and station of main Points 2- Coordinates of station (P.C and P.T) OR T ③ C LTRA 188 Д T = R tan A C=2R sin 2 D E=RL-c's + -1) A 2 M=R (1- Cos) sta PC sta PI - T sta P.T= sta P.C+L L DE ⑥M P.I P.C T T R PT
Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
5th Edition
ISBN:9781305084766
Author:Saeed Moaveni
Publisher:Saeed Moaveni
Chapter7: Length And Length-related Variables In Engineering
Section: Chapter Questions
Problem 42P
Related questions
Question
![Asimple horizontal curve has: A = 46" 18" L = 215m
Station PC = (15+25), Coordinate of P.I = (450, 620) and Azimuth
of (P.I P.T) =112° 18' calculate:
1-All elements and station of main Points
2- Coordinates of station (P.C and P.T)
OR
T ③ C
LTRA
188
Д
T = R tan A
C=2R sin
2
D
E=RL-c's + -1)
A
2
M=R (1- Cos)
sta PC sta PI - T
sta P.T= sta P.C+L
L DE
⑥M
P.I
P.C
T
T
R
PT](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F758f75dc-8829-4ab0-92c2-5908251797f8%2F37ca447a-c0b8-4e27-982e-dbfd11da3e02%2Fpb4bb0g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Asimple horizontal curve has: A = 46" 18" L = 215m
Station PC = (15+25), Coordinate of P.I = (450, 620) and Azimuth
of (P.I P.T) =112° 18' calculate:
1-All elements and station of main Points
2- Coordinates of station (P.C and P.T)
OR
T ③ C
LTRA
188
Д
T = R tan A
C=2R sin
2
D
E=RL-c's + -1)
A
2
M=R (1- Cos)
sta PC sta PI - T
sta P.T= sta P.C+L
L DE
⑥M
P.I
P.C
T
T
R
PT
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