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(i) Reinforced Masonry Wall Internally E = 500,000 ton/m2 E/G = 2.5 Thickness = 0.15 m 2.5 m 2.5 m (i) A = ? 1 = ? f = ? Equivalent bar reinforced concrete deformable by flexion and axial 2.5 m E = 2'000,000 ton/m2 (i) * Results: A = 0.025 m2 2.0 m I = 0.01267 m4 f = 0

(i) Reinforced Masonry Wall Internally E = 500,000 ton/m2 E/G = 2.5 Thickness = 0.15 m 2.5 m 2.5 m (i) A = ? 1 = ? f = ? Equivalent bar reinforced concrete deformable by flexion and axial 2.5 m E = 2'000,000 ton/m2 (i) * Results: A = 0.025 m2 2.0 m I = 0.01267 m4 f = 0

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Determine the characteristics of the equivalent bar (area, moment of inertia and shape factor of the cross section) that allows replacing the wall of three basements shown.

Data:

Reinforced Masonry Wall Internally:

E = 500,000 ton/m2

E/G = 2.5

Thickness = 0.15 m

Base: 2.0m

Height of each basement wall: 2.5m

Equivalent bar reinforced concrete deformable by flexion and axial: E = 2,000,000 ton/m2

 

(i) Reinforced Masonry Wall Internally E = 500,000 ton/m2 E/G = 2.5 Thickness = 0.15 m 2.5 m 2.5 m (i) A = ? 1 = ? f = ? Equivalent bar reinforced concrete deformable by flexion and axial 2.5 m E = 2'000,000 ton/m2 (i) * Results: A = 0.025 m2 2.0 m I = 0.01267 m4 f = 0
Transcribed Image Text:(i) Reinforced Masonry Wall Internally E = 500,000 ton/m2 E/G = 2.5 Thickness = 0.15 m 2.5 m 2.5 m (i) A = ? 1 = ? f = ? Equivalent bar reinforced concrete deformable by flexion and axial 2.5 m E = 2'000,000 ton/m2 (i) * Results: A = 0.025 m2 2.0 m I = 0.01267 m4 f = 0
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