Given: POST-TENSIONED BEAM with A PARABOLIC TENDON PROFILE Span Length = 20 m fi = 1200 N/mm² A, = 2850 mm² Ac = 4.23x105 mm² 1=9.36x10¹0 mm* e-560 mm (@midspan, from N.A.) f'c= 40 N/mm² Es = 210,000 N/mm². μ = 0.19 K = 0.0005 (per meter) Anchorage slip = 5 mm (jacked at left-end only) (make sure to draw the force variation diagram for anchorage slip)
Given: POST-TENSIONED BEAM with A PARABOLIC TENDON PROFILE Span Length = 20 m fi = 1200 N/mm² A, = 2850 mm² Ac = 4.23x105 mm² 1=9.36x10¹0 mm* e-560 mm (@midspan, from N.A.) f'c= 40 N/mm² Es = 210,000 N/mm². μ = 0.19 K = 0.0005 (per meter) Anchorage slip = 5 mm (jacked at left-end only) (make sure to draw the force variation diagram for anchorage slip)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Determine the losses in the post-tensioned concrete beam as shown below.
560 mm
Given: POST-TENSIONED BEAM with A PARABOLIC TENDON PROFILE
Span Length = 20 m
fi = 1200 N/mm²
A, = 2850 mm²
Ac 4.23x105 mm²
1=9.36x10¹0 mm
e-560 mm (@midspan, from N.A.)
fc= 40 N/mm²
Es = 210,000 N/mm²
μ = 0.19
K = 0.0005 (per meter)
Anchorage slip = 5 mm (jacked at left-end only).
(make sure to draw the force variation diagram for anchorage slip)
V/S= 6
RH = 70
Dead Load 9.97 kN/m
fpy = 1714 N/mm²
Bridge Width
III
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